场景:我有一个带有2个选择的表格。当用户从第一个选择中选择某项时,第二个选择将填充新值。这部分工作正常。
但是该表单未得到验证,因为它包含初始表单中不允许的某些选项。
形式:
<?php
class MyType extends AbstractType
{
private $category;
public function __construct($category = null)
{
$this->category = $category;
}
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('category', 'choice', array(
'choices' => array(
'foo' => 'foo',
'bar' => 'bar'
)
);
$builder->add('template', 'choice', array(
'choices' => $this->loadChoices()
);
}
private function loadChoices()
{
// load them from DB depending on the $this->category
}
}
最初,类别为
foo
。因此,将foo的模板加载并设置为选项。但是,如果用户选择bar
,则将加载条形模板。但是该表格仍然具有foo选项,并且无法验证。解决此问题的最佳方法是什么?
我发现的一种方法是仅在 Controller 中重新初始化表单:
<?php
$form = $this->createForm(new MyType());
if ($request->getMethod() === 'POST') {
if ($request->request->has($form->getName())
&& isset($request->request->get($form->getName())['category'])) {
$form = $this->createForm(new MyType($request->request->get($form->getName())['category']));
}
// ...
}
这行得通,但是我无法测试它,因为在设置该值时会抛出
IllegalArgumentException
,并且仅假设默认值。有什么更好的解决方案吗?提前致谢! 最佳答案
我认为您必须使用事件来管理此问题,这是更正确的方法
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder->add('category', 'choice', array(
'choices' => array(
'foo' => 'foo',
'bar' => 'bar'
)
));
$ff = $builder->getFormFactory();
// function to add 'template' choice field dynamically
$func = function (FormEvent $e) use ($ff) {
$data = $e->getData();
$form = $e->getForm();
if ($form->has('template')) {
$form->remove('template');
}
$cat = isset($data['category'])?$data['category']:null;
// here u can populate ur choices in a manner u do it in loadChoices
$choices = array('1' => '1', '2' => '2');
if ($cat == 'bar') {
$choices = array('3' => '3', '4' => '4');
}
$form->add($ff->createNamed('template', 'choice', null, compact('choices')));
};
// Register the function above as EventListener on PreSet and PreBind
$builder->addEventListener(FormEvents::PRE_SET_DATA, $func);
$builder->addEventListener(FormEvents::PRE_BIND, $func);
}