运行代码时,我面临以下错误。
错误-列标签“ Avg_Threat_Score”不是唯一的。

我正在创建数据透视表,并希望将值从高到低排序。

pt = df.pivot_table(index = 'User Name',values = ['Threat Score', 'Score'],
        aggfunc = {
                   'Threat Score': np.mean,
                   'Score' :[np.mean, lambda x: len(x.dropna())]
                  },
        margins = False)

new_col =['User Name Count', 'AVG_TH_Score', 'Avg_Threat_Score']
pt.columns = [new_col]
#befor this code is working, after that now working
df = df.reindex(pt.sort_values
                    (by = 'Avg_Threat_Score',ascending=False).index)


需要对“ Avg_Threat_Score”列的值进行高低排序

最佳答案

您需要按列表(而不是嵌套列表)传递新的列名称,因为熊猫会在一个级别上创建MultiIndex

new_col =['User Name Count', 'AVG_TH_Score', 'Avg_Threat_Score']
pt.columns = [new_col]


是一样的:

pt.columns = [['User Name Count', 'AVG_TH_Score', 'Avg_Threat_Score']]



  ValueError:列标签“ Avg_Threat_Score”不是唯一的。
  对于多索引,标签必须是一个元组,其元素与每个级别相对应。


因此使用:

pt.columns = ['User Name Count', 'AVG_TH_Score', 'Avg_Threat_Score']


样品:

df = pd.DataFrame({
        'User Name':list('ababaa'),
         'Threat Score':[4,5,4,np.nan,5,4],
         'Score':[np.nan,8,9,4,2,np.nan],
         'D':[1,3,5,7,1,0]})

pt = (df.pivot_table(index = 'User Name',values = ['Threat Score', 'Score'],
        aggfunc = {
                   'Threat Score': np.mean,
                   'Score' :[np.mean, lambda x: len(x.dropna())]
                  },
        margins = False))

pt.columns = ['User Name Count', 'AVG_TH_Score', 'Avg_Threat_Score']
print (pt)
           User Name Count  AVG_TH_Score  Avg_Threat_Score
User Name
a                      2.0           5.5              4.25
b                      2.0           6.0              5.00


然后对于从Avg_Threat_Score排序的排序,请对列Categorical使用排序的User Name,因此最后一个sort_values工作:

names = pt.sort_values(by = 'Avg_Threat_Score',ascending=False).index
print (names)
#Index(['b', 'a'], dtype='object', name='User Name')

df['User Name'] = pd.CategoricalIndex(df['User Name'], categories=names, ordered=True)
df = df.sort_values('User Name')




print (df)
  User Name  Threat Score  Score  D
1         b           5.0    8.0  3
3         b           NaN    4.0  7
0         a           4.0    NaN  1
2         a           4.0    9.0  5
4         a           5.0    2.0  1
5         a           4.0    NaN  0

关于python - 如何解决“列标签'Avg_Threat_Score'不是唯一的”。起诉 Pandas ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/56312312/

10-12 17:04
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