我有这个功能
function getStudents() {
var students = [];
students[0] = {name: "Anna", mark: 65, sex: "female"};
students[1] = {name: "James", mark:33, sex: "male"};
students[2] = {name: "William", mark: 87, sex: "male"};
students[3] = {name: "Jane", mark: 72, sex: "female"};
students[4] = {name: "Rikki", mark: 60, sex: "male"};
students[5] = {name: "Angela", mark: 58, sex: "female"};
}
然后在体内,我尝试这样做:
var students = getStudents();
var referrals = ["James", "Angela"];
for(var i = 0; i < students.length; i++){
var pTag ="<p>";
但是,当我尝试遍历循环时,它告诉我它不能执行未定义变量的.length,但是我想我已经通过调用函数并将其分配给变量来定义它了?
最佳答案
更改此代码的功能。问题是您没有返回变量student,并且当您超出范围时该变量不再存在。使用return可以在调用函数时将其分配给变量。
function getStudents() {
var students = [];
students[0] = {name: "Anna", mark: 65, sex: "female"};
students[1] = {name: "James", mark:33, sex: "male"};
students[2] = {name: "William", mark: 87, sex: "male"};
students[3] = {name: "Jane", mark: 72, sex: "female"};
students[4] = {name: "Rikki", mark: 60, sex: "male"};
students[5] = {name: "Angela", mark: 58, sex: "female"};
return students;
}