我有一个MyDatabase.MyTable.DateCol
包含几千行,我想用日期时间填充它。我希望每个日期都比前一个日期大1秒。我怎样才能做到这一点?
最佳答案
样品表
CREATE Table DateTable
(ID INT IDENTITY(1,1),Name NVARCHAR(300), Data Datetime)
GO
测试数据
INSERT INTO DateTable (Name)
VALUES ('John'),('Mark'),('Phil'),('Simon'),('Sam'),('Pete'),('Josh')
GO
询问
;WITH CTE
AS
(
SELECT *, rn = ROW_NUMBER() OVER (ORDER BY ID ASC) FROM DateTable
)
UPDATE CTE
SET Data = DATEADD(SECOND, CTE.rn, GETDATE())
结果集
SELECT * FROM DateTable
ID Name Data
1 John 2013-11-06 20:34:59.310
2 Mark 2013-11-06 20:35:00.310
3 Phil 2013-11-06 20:35:01.310
4 Simon 2013-11-06 20:35:02.310
5 Sam 2013-11-06 20:35:03.310
6 Pete 2013-11-06 20:35:04.310
7 Josh 2013-11-06 20:35:05.310
关于sql - 填充表,日期时间每增加一秒,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/19821823/