假设我有一个在div或UL下的项目列表。我想采用具有相同title属性的所有列表项,并在其周围包裹一个UL。不过,下一部分是我希望UL处于具有相同属性的LI下。因此,我正在尝试基本分组。
所以...我从...开始
<li>Insurance</li>
<li>Education</li>
<li>Sports</li>
<li>Construction</li>
<li title ="Insurance">Malpractice</li>
<li title ="Construction">Carpentry</li>
<li title ="Education">College</li>
<li title ="Insurance">Automobile</li>
<li title ="Education">High School</li>
<li title ="Construction">Iron Worker</li>
我想去......
<li>Insurance
<ul>
<li title ="Insurance">Malpractice</li>
<li title ="Insurance">Automobile</li>
</ul>
</li>
<li>Education
<ul>
<li title ="Education">College</li>
<li title ="Education">High School</li>
</ul>
</li>
<li>Sports</li>
<li>Construction
<ul>
<li title ="Construction">Carpentry</li>
<li title ="Construction">Iron Worker</li>
</ul>
</li>
任何帮助,将不胜感激。显然对于jquery和javascript世界来说是新事物,所以我正尽力解决这一问题。
最佳答案
// first we fetch all items without title attribute
var topLevel = $('li:not([title])');
// for each of those...
topLevel.each(function() {
var li = $(this),
// ... we get its text ...
title = li.text(),
// ... and other li elements with the corresponding title
children = $('li[title="' + title + '"]');
// if there are any...
if (children.length > 0) {
// ... create an empty list ...
var ul = $('<ul></ul>');
// ... fill it and ...
children.appendTo(ul);
// ... append it to the original li element
ul.appendTo(li);
}
});
jQuery文档:
:not()
, [title]
, each()
, appendTo()