所有,

遇到ConcurrentModificationException的问题,并且努力找到解决方案的部分原因是在迭代过程中看不到修改列表的位置...有什么想法吗?我突出显示了导致问题的行(it3.remove())。真的停滞了。

编辑:Stacktrace:

Exception in thread "Thread-4" java.util.ConcurrentModificationException
    at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
    at java.util.ArrayList$Itr.next(Unknown Source)
    at com.shimmerresearch.advancepc.InternalFrameAndPlotManager.subtractMaps(InternalFrameAndPlotManager.java:1621)


第1621行对应于我上面引用的代码中的it3.remove()。

private void subtractMaps(ConcurrentSkipListMap<String, PlotDeviceDetails> firstMap, ConcurrentSkipListMap<String, PlotDeviceDetails> secondMap) {

    // iterate through the secondmap
    Iterator<Entry<String, PlotDeviceDetails>> it1 = secondMap.entrySet().iterator();
    while (it1.hasNext()) {
        Entry<String, PlotDeviceDetails> itEntry = (Entry) it1.next();
        String mapKey = (String) it1Entry.getKey();
        PlotDeviceDetails plotDeviceDetails = (PlotDeviceDetails)it1Entry.getValue();

        // if we find an entry that exists in the second map and not in the first map continue
        if(!firstMap.containsKey(mapKey)){
            continue;
        }

         // iterate through a list of channels belonging to the secondmap
        Iterator <PlotChannelDetails> it2 = plotDeviceDetails.mListOfPlotChannelDetails.iterator();
        while (it2.hasNext()) {
            PlotChannelDetails it2Entry = it2.next();

            // iterate through a list of channels belonging to the firstmap
            Iterator <PlotChannelDetails> it3 = firstMap.get(mapKey).mListOfPlotChannelDetails.iterator();
            innerloop:
            while(it3.hasNext()){
                // if a channel is common to both first map and second map, remove it from firstmap
                PlotChannelDetails it3Entry = it3.next();
                if(it3Entry.mChannelDetails.mObjectClusterName.equals(it2Entry.mChannelDetails.mObjectClusterName)){
                    it3.remove(); // this line is causing a concurrentModificationException
                    break innerloop;
                }
            }
        }
    }
}

最佳答案

plotDeviceDetails.mListOfPlotChannelDetailsfirstMap.get(mapKey).mListOfPlotChannelDetails引用相同的列表。

没有更多信息,未知plotDeviceDetailsfirstMap.get(mapKey)是否还引用同一对象,但是它们共享通道列表。

10-07 13:22
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