经过大量研究,我仍然感到困惑。我有一个连续读取数据的串行端口对象。我能够执行的操作将生成dataReceived事件,与端口进行通信,并将接收到的值输出到调试窗口。因此,我很确定这一切都可以正常进行。问题是,当我尝试将串行端口输出传递到我的原始线程时,出现错误。它说我不能进行线程串扰(或类似的事情)。我一直在尝试使用backgroundWorker,但是我不确定这是我想要的解决方案,加上我的新手技能,这会有点麻烦。而且我尝试使用invoke,但是该方法似乎不可用。 (我可能是从错误的对象打电话来的?)无论如何,下面的部分。
namespace Photometer
{
class csRadiometerILT1700
{
//manufacturer specs for baud rate, databits, and stop bits
static string portName="COM1";
static int baudRate = 1200;
static int dataBits = 8;
//instantialize a serial port object for the Radiometer
private SerialPort RadiometerSerial = new SerialPort(portName, baudRate, Parity.None, dataBits, StopBits.One);
//constructor
//public csRadiometerILT1700(Form ParentForm, Chart outputChart)
public csRadiometerILT1700()
{
//two handshaking properties of the ILT1700. Handshaking is enabled and
//http://stackoverflow.com/questions/6277619/problem-reading-serial-port-c-net-2-0-to-get-weighing-machine-output
RadiometerSerial.Handshake= Handshake.RequestToSend;
RadiometerSerial.DtrEnable = true;
RadiometerSerial.DataReceived += new SerialDataReceivedEventHandler(RadiometerSerial_DataReceived);
}
public void openPort()
{
if (!RadiometerSerial.IsOpen)
{
RadiometerSerial.Open();
}
}
public void closePort()
{
RadiometerSerial.Close();
}
string RadiometerVoltageReadingString;
int RadiometerVoltageReadingInt;
private void RadiometerSerial_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
//It's here that this.invoke()... cannot be called.
RadiometerVoltageReadingString= (RadiometerSerial.ReadExisting().ToString()); //y-value
Debug.Print(RadiometerVoltageReadingString.ToString());
makeRadioReadingDouble(RadiometerVoltageReadingString);
}
private void makeRadioReadingDouble(string inputVoltageString)
{
List<double> outputVoltageDouble=new List<double>(2);
if (!(inputVoltageString == "\r\n" || inputVoltageString == ""))
{
string[] voltageValAndExpo = inputVoltageString.Split(new string[] { "e", "\r\n" }, StringSplitOptions.RemoveEmptyEntries);
for (int inCounter = 0; inCounter < voltageValAndExpo.Count(); inCounter=inCounter+2)
{
double voltageVal = Convert.ToDouble(voltageValAndExpo[inCounter]);
double voltageExpo = Convert.ToDouble(voltageValAndExpo[inCounter + 1]);
outputVoltageDouble.Add(Math.Pow(voltageVal, voltageExpo));
}
}
}
}
}
当我用代码形成负载时,所有这些都被称为
csRadiometerILT1700 Radiometer;
...
Radiometer = new csRadiometerILT1700();
Radiometer.openPort();
任何见解均表示赞赏。
编辑:
我将csRadiometerILT1700构造函数更改为
public csRadiometerILT1700(Form inputForm)
{
//inputForm.Invoke(
//two handshaking properties of the ILT1700. Handshaking is enabled and
//http://stackoverflow.com/questions/6277619/problem-reading-serial-port-c-net-2-0-to-get-weighing-machine-output
RadiometerSerial.Handshake= Handshake.RequestToSend;
RadiometerSerial.DtrEnable = true;
RadiometerSerial.DataReceived += new SerialDataReceivedEventHandler(RadiometerSerial_DataReceived);
inputForm.Invoke(DataReceived);
}
并声明
public event Delegate DataReceived;
在csRadiometerILT1700类中。但这给了我一个错误:“Datareceived必须是委托(delegate)类型。”我现在该如何解决?我在正确的轨道上吗?
最佳答案
RadiometerILT1700
类需要一个event
来报告其已接收(和已处理)的数据。 this.Invoke()
来克服跨线程问题。