如果我具有以下设置,那么在同一上下文中创建对象时,如何配置我的容器以使用同一数据库
public class Database { }
public interface IRepository { Database Database { get; } }
public interface IFooRepository : IRepository { }
public interface IBarRepository : IRepository { }
public class FooRepository : IFooRepository
{
public Database Database { get; private set; }
public FooRepository(Database database) { this.Database = database; }
}
public class BarRepository : IBarRepository
{
public Database Database { get; private set; }
public BarRepository(Database database) { this.Database = database; }
}
public class Consumer
{
public IFooRepository fooRepository { get; private set; }
public IBarRepository barRepository { get; private set; }
public Consumer(IFooRepository fooRepository, IBarRepository barRepository)
{
this.fooRepository = fooRepository;
this.barRepository = barRepository;
}
}
[TestClass]
public class ConfigurationTest
{
private IWindsorContainer container;
[TestMethod]
public void SameDatabaseIsUsed()
{
Consumer consumer = container.Resolve<Consumer>();
IFooRepository fooRepository = consumer.fooRepository;
IBarRepository barRepository = consumer.barRepository;
Assert.AreEqual(fooRepository.Database, barRepository.Database); //FAILS
}
[TestMethod]
public void DifferentDatabaseIsUsed()
{
Consumer consumer = container.Resolve<Consumer>();
IFooRepository fooRepository = consumer.fooRepository;
Consumer consumer2 = container.Resolve<Consumer>();
IBarRepository barRepository = consumer2.barRepository;
Assert.AreNotEqual(fooRepository.Database, barRepository.Database); //PASSES
}
[TestInitialize]
public void SetUp()
{
container = new WindsorContainer();
container.Register(
Component.For<Database>().ImplementedBy<Database>().LifeStyle.Transient,
AllTypes.FromThisAssembly()
.BasedOn<IRepository>().WithService.FromInterface()
.Configure(c => c.LifeStyle.Transient),
Component.For<Consumer>().ImplementedBy<Consumer>().LifeStyle.Transient
);
}
}
编辑:
我试图使用自定义的生活方式,但是我无法弄清楚我可以用来检测是否切换了上下文
public class DatabaseLifestyleManager : AbstractLifestyleManager
{
private CreationContext context;
private Database database;
private Database Database
{
get
{
if (database == null) database = new Database();
return database;
}
set
{
database = null;
}
}
public override object Resolve(CreationContext context)
{
if (this.context!=null && this.context.??? == context.???)
return Database;
else
{
this.context = context;
Database = null;
return Database;
}
}
public override void Dispose()
{
database = null;
context = null;
}
}
......
Component.For<Database>().ImplementedBy<Database>().LifeStyle.Custom(typeof(DatabaseLifestyleManager)
最佳答案
请求瞬态组件时,您总是会得到一个新实例,如果不是您想要的实例,请不要使用瞬态生活方式:-)
您为什么要注册一个瞬态组件,而尝试根据某种“上下文”来解析同一对象?生活方式很可能是这种情况的错误,而您会很难将其强迫为并非如此。
您想要的是类似于this article中提到的上下文生活方式。
以下两个要点对此有一个实现:
http://gist.github.com/400979
http://gist.github.com/400980
这将允许您执行以下操作:
Register(Component.For<Database>().LifeStyle.Scoped())
[TestMethod]
public void SameDatabaseIsUsed()
{
using (container.BeginScope())
{
Consumer consumer = container.Resolve<Consumer>();
IFooRepository fooRepository = consumer.fooRepository;
IBarRepository barRepository = consumer.barRepository;
Assert.AreEqual(fooRepository.Database, barRepository.Database); // YAY!
}
}
希望这可以帮助!
关于dependency-injection - 如何在相同的上下文中使用CaSTLe Windsor DI容器重用 transient 依赖项,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/3986747/