我想获取在member_total_point
处的MONTH(NOW())
列与在MONTH(NOW() INTERVAL 1 MONTH)
处的列相加的表。如何选择表格?
编辑
我不应该在选择上使用[..]
这是我的新查询:
SELECT la.member_created, la.member_api_domain, la.member_api_campaign,
la.total, lb.total_now
FROM (SELECT member_created, member_api_domain, member_api_campaign, SUM(member_total_point) AS 'total'
FROM lalights_member WHERE YEAR(member_created)=YEAR(NOW())
AND MONTH(member_created)= MONTH(NOW()-INTERVAL 1 MONTH)
GROUP BY member_api_campaign ) AS la
LEFT JOIN (SELECT member_created,SUM(member_total_point)
AS 'total_now'
FROM lalights_member WHERE YEAR(member_created)=YEAR(NOW())
AND MONTH(member_created)= MONTH(NOW())
ORDER BY member_api_campaign DESC) AS lb
ON la.member_created = lb.member_created
但是错误出现在SQLyog上:
'[total],lb. [total_now] FROM(选择第1行的member_created,member_api_domain,member_a'
即时通讯使用MySQL 5.1 ..
样本数据:
member_created member_api_domain member_api_campaign member_total_point
-------------- ----------------- ------------------- ------------------
2015-09-22 18:30:20 domain campaign 4 (september)
2015-09-22 18:30:20 domain campaign 7 (september)
2015-08-22 18:30:20 domain campaign 2 (august)
2015-08-22 18:30:20 domain campaign 7 (august)
2015-09-22 18:30:20 asdf jujuju 4 (september)
2015-08-22 18:30:20 asdf jujuju 9 (august)
样本输出:
member_api_campaign this_month last_1month last_2month
------------------- ---------- ----------- -----------
domain campaign 11(september) 9 (august)
asdf jujuju 4 (september) 9 (august)
提醒一下,现在是
October
。 最佳答案
更改单引号(平均字符串)作为边引号,或仅删除字段别名的引号
'total' for `total`
'total_now' for `total_now`
删除
ORDER BY member_api_campaign DESC
。
SELECT la.member_created
,la.member_api_domain
,la.member_api_campaign
,la.total
,lb.total_now
FROM (
SELECT member_created
,member_api_domain
,member_api_campaign
,SUM(member_total_point) AS 'total'
FROM lalights_member
WHERE YEAR(member_created) = YEAR(NOW())
AND MONTH(member_created) = MONTH(NOW() - INTERVAL 1 MONTH)
GROUP BY member_api_campaign
) AS la
LEFT JOIN (
SELECT member_created
,SUM(member_total_point) AS 'total_now'
FROM lalights_member
WHERE YEAR(member_created) = YEAR(NOW())
AND MONTH(member_created) = MONTH(NOW())
) AS lb ON la.member_created = lb.member_created
关于mysql - 将同一表中的两个查询连接到不同的月份和总和值,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33427717/