关于系统:
-有些辅导老师创建课程和课程包
-遵循基于标签的搜索方法。当新的导师注册并且导师创建包时,将创建标签关系(这使导师和包可搜索)。有关详细信息,请检查标签在该系统中如何工作?下面。

以下是相关查询
有人可以帮我建议使用临时表的方法吗?我们已经索引了所有相关字段,并且看来这是使用这种方法的最少时间:

 SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%"
                      OR tt.tag LIKE "%Dictatorship%"
                      OR ttt.tag LIKE "%Dictatorship%" )) AS key_1_total_matches
       ,
       SUM(DISTINCT( t.tag LIKE "%democracy%"
                      OR tt.tag LIKE "%democracy%"
                      OR ttt.tag LIKE "%democracy%" ))    AS key_2_total_matches
       ,
       COUNT(DISTINCT( od.id_od ))                        AS
       tutor_popularity,
       CASE
         WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1
                                       AND wc.wc_type = 0
                                       AND wc.class_date > '2010-06-01 22:00:56'
                                       AND wccp.status = 1
                                       AND ( wccp.country_code = 'IE'
                                              OR wccp.country_code IN ( 'INT' )
                                           ) ), 0)
              ) THEN 1
         ELSE 0
       END                                                AS 'classes_published'
       ,
       CASE
         WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1
                                       AND lp.published = 1
                                       AND lpcp.status = 1
                                       AND ( lpcp.country_code = 'IE'
                                              OR lpcp.country_code IN ( 'INT' )
                                           ) ), 0)
              ) THEN 1
         ELSE 0
       END                                                AS 'packs_published',
       td . *,
       u . *
FROM   tutor_details AS td
       JOIN users AS u
         ON u.id_user = td.id_user
       LEFT JOIN learning_packs_tag_relations AS lptagrels
         ON td.id_tutor = lptagrels.id_tutor
       LEFT JOIN learning_packs AS lp
         ON lptagrels.id_lp = lp.id_lp
       LEFT JOIN learning_packs_categories AS lpc
         ON lpc.id_lp_cat = lp.id_lp_cat
       LEFT JOIN learning_packs_categories AS lpcp
         ON lpcp.id_lp_cat = lpc.id_parent
       LEFT JOIN learning_pack_content AS lpct
         ON ( lp.id_lp = lpct.id_lp )
       LEFT JOIN webclasses_tag_relations AS wtagrels
         ON td.id_tutor = wtagrels.id_tutor
       LEFT JOIN webclasses AS wc
         ON wtagrels.id_wc = wc.id_wc
       LEFT JOIN learning_packs_categories AS wcc
         ON wcc.id_lp_cat = wc.id_wp_cat
       LEFT JOIN learning_packs_categories AS wccp
         ON wccp.id_lp_cat = wcc.id_parent
       LEFT JOIN order_details AS od
         ON td.id_tutor = od.id_author
       LEFT JOIN orders AS o
         ON od.id_order = o.id_order
       LEFT JOIN tutors_tag_relations AS ttagrels
         ON td.id_tutor = ttagrels.id_tutor
       LEFT JOIN tags AS t
         ON t.id_tag = ttagrels.id_tag
       LEFT JOIN tags AS tt
         ON tt.id_tag = lptagrels.id_tag
       LEFT JOIN tags AS ttt
         ON ttt.id_tag = wtagrels.id_tag
WHERE  ( u.country = 'IE'
          OR u.country IN ( 'INT' ) )
       AND CASE
             WHEN ( ( tt.id_tag = lptagrels.id_tag )
                    AND ( lp.id_lp > 0 ) ) THEN lp.id_status = 1
                                                AND lp.published = 1
                                                AND lpcp.status = 1
                                                AND ( lpcp.country_code = 'IE'
                                                       OR lpcp.country_code IN (
                                                          'INT'
                                                          ) )
             ELSE 1
           END
       AND CASE
             WHEN ( ( ttt.id_tag = wtagrels.id_tag )
                    AND ( wc.id_wc > 0 ) ) THEN wc.wc_api_status = 1
                                                AND wc.wc_type = 0
                                                AND
             wc.class_date > '2010-06-01 22:00:56'
                                                AND wccp.status = 1
                                                AND ( wccp.country_code = 'IE'
                                                       OR wccp.country_code IN (
                                                          'INT'
                                                          ) )
             ELSE 1
           END
       AND CASE
             WHEN ( od.id_od > 0 ) THEN od.id_author = td.id_tutor
                                        AND o.order_status = 'paid'
                                        AND CASE
             WHEN ( od.id_wc > 0 ) THEN od.can_attend_class = 1
             ELSE 1
                                            END
             ELSE 1
           END
       AND ( t.tag LIKE "%Dictatorship%"
              OR t.tag LIKE "%democracy%"
              OR tt.tag LIKE "%Dictatorship%"
              OR tt.tag LIKE "%democracy%"
              OR ttt.tag LIKE "%Dictatorship%"
              OR ttt.tag LIKE "%democracy%" )
GROUP  BY td.id_tutor
HAVING key_1_total_matches = 1
       AND key_2_total_matches = 1
ORDER  BY tutor_popularity DESC,
          u.surname ASC,
          u.name ASC
LIMIT  0, 20


问题

上述查询返回的结果是正确的(AND逻辑按预期工作),但是对于较重的数据,查询所花费的时间令人震惊地增加,对于我拥有的当前数据,该查询的时间大约为10秒,与订单的正常查询时间相比0.005-0.0002秒,这使其完全不可用。

有人在我之前的问题中建议执行以下操作:


创建一个临时表,并在此处插入所有可能最终结果集中的相关数据
在此表上运行多个更新,一次连接一个所需的表,而不是一次连接所有的表
最后对此临时表执行查询以提取最终结果


所有这些都是在存储过程中完成的,最终结果已经通过了单元测试,并且发展迅速。

到目前为止,我从未使用过临时表。仅当我能获得一些提示时,才能使用示意图表示,以便从...开始。

查询有问题吗?
超过10秒的执行时间会是什么原因?

标签在此系统中如何工作?


当教师注册时,将输入标签并根据教师的详细信息(例如姓名,姓氏等)创建标签关系。
当辅导员创建包时,将再次输入标签,并根据包的详细信息(如包名称,说明等)创建标签关系。
存储在tutors_tag_relations中的导师的标签关系以及存储在learning_packs_tag_relations中的包的标签关系。所有单个标签都存储在标签表中。

最佳答案

临时表不是万灵丹。查询的基本问题在于以下模式:

   t.tag LIKE "%Dictatorship%"
OR tt.tag LIKE "%Dictatorship%"
OR ttt.tag LIKE "%Dictatorship%"


在LIKE比较的左侧通配符可确保无法使用索引。实际上,您正在扫描所有涉及的三个表...

您需要利用MySQL's native FTS或Sphinx之类的第三方工具进行全文搜索。我所知道的所有FTS都包含一个得分/等级值,表示比赛的强度-you can read the MySQL documentation for the algorithm details。但是分数/排名与您获得的分数不同:SUM(DISTINCT LIKE...),您可以使用类似的方法获得相同的分数:

  SELECT t.id_tag,
         COUNT(*) AS num_matches
    FROM TABGS
   WHERE MATCH(tag) AGAINST ('Dictatorship')
GROUP BY t.id_tag

关于mysql - 帮助我将单个复杂查询更改为使用临时表,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/3006801/

10-11 05:35
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