我正在使用此代码列出按类型计算和分类的卡车类型列表。
$count['type'] = $this->Type->find('all',
array('joins' => array(
array(
'table' => 'truck_has_types',
'alias' => 'TruckHasTypes',
'type' => 'LEFT',
'conditions' => array(
'Type.id' => 'TruckHasTypes.types_id',
)
)
),
'fields' => array(
'Type.id',
'Type.name',
'COUNT(TruckHasTypes.types_id) as N'),
'group' => 'TruckHasTypes.types_id'
)
);
该查询仅返回单个结果,即使认为应该有更多结果。我找到了罪魁祸首。查询看起来像这样(从sql_dump中获得了此信息)
SELECT `Type`.`id`, `Type`.`name`, COUNT(`TruckHasTypes`.`types_id`) as N FROM `douglass_cake`.`types` AS `Type` LEFT JOIN `douglass_cake`.`truck_has_types` AS `TruckHasTypes` ON (`Type`.`id` = 'TruckHasTypes.types_id') WHERE 1 = 1 GROUP BY `TruckHasTypes`.`types_id`
你可以看到
ON (`Type`.`id` = 'TruckHasTypes.types_id')
没有相同的引号
ON (`Type`.`id` = `TruckHasTypes`.`types_id`)
我已经在phpmyadmin中手动添加了这些引号,并且查询成功,但是我无法让cakephp自动生成此查询。有任何想法吗?
谢谢!
瑞安
最佳答案
这样做:
$count['type'] = $this->Type->find('all',
array(
'joins' => array(
array(
'table' => 'truck_has_types',
'alias' => 'TruckHasTypes',
'type' => 'LEFT',
'conditions' => array(
'Type.id=TruckHasTypes.types_id',
)
)
),
'fields' => array(
'Type.id',
'Type.name',
'COUNT(TruckHasTypes.types_id) as N'
),
'group' => 'TruckHasTypes.types_id'
)
);
关于php - CakePHP发现未在查询中插入正确的引号,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/25585860/