php - PHP PDO动态查询构建

$arr = array();
$from_date = '2015-01-01';
$to_date = '2015-01-31';
$order_no = '25215';
$sql = "SELECT * FROM test";
if(!empty($from_date)&&!empty($to_date))
{
    $sql.=" WHERE txn_date BETWEEN :from_date AND :to_date";
    $arr[] = ":from_date => $from_date";
    $arr[] = ":to_date => $to_date";
    $condition=true;
}
if(!empty($order_no))
{
    if($condition)
    {
       $sql.=" AND ref_number = :order_no";
       $arr[] = ":order_no => $order_no";
    }
    else
    {
       $sql.=" WHERE ref_number = :order_no";
       $arr[] = ":order_no => $order_no";
       $condition=true;
    }
}
$stmt = $db->prepare($sql);
$stmt->execute($arr);
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);

执行此查询时显示警告类似


  警告：PDOStatement :: execute（）：SQLSTATE [HY093]：无效的参数编号：参数未定义


怎么了

最佳答案

在变量$ arr中，您应像这样替换所有关联索引

$arr[':from_date'] = $from_date;
$arr[':to_date'] = $to_date;
$arr[':order_no'] = $order_no;

同样好的做法是在外部块中移动通用代码，而不是if / else梯形图

if(!empty($order_no))
{
    $arr[':order_no'] = $order_no;
    if($condition)
    {
       $sql.=" AND ref_number = :order_no";
    }
    else
    {
       $sql.=" WHERE ref_number LIKE :order_no";
       $condition=true;
    }
}

正如op在评论中所问的那样，这是对此的解释

$sql.=" WHERE txn_date BETWEEN :from_date AND :to_date";

用这个代替

$sql.=" WHERE date(txn_date) BETWEEN date(:from_date) AND date(:to_date)";

ref_number = :order_no

在if / else语句的两个where条件中，都将上述类型强制转换为无符号整数，如下所示

CONVERT(ref_number,UNSIGNED INTEGER) = :order_no

关于php - PHP PDO动态查询构建，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/29960014/