php - 使用find()方法查询cakePHP

如何转换此查询以使用cakePHP的方法find()？

查询：

SELECT Ch.id, COUNT( DU.d_id ) AS a, SUM(DU.d_id) AS b
FROM c AS Ch
LEFT JOIN du AS DU ON DU.c_id = Ch.id AND MONTH( DU.created ) = MONTH( NOW( ) )
LEFT JOIN d AS D ON DU.d_id = D.id
GROUP BY Ch.id

最佳答案

$Ch->find(
    'all',
    'fields' => array(
               'Ch.id','COUNT( DU.d_id ) AS a', 'SUM(DU.d_id) AS b'),
    'joins'  => array(
                      array(
                            'table' => 'du',
                            'alias' => 'DU',
                            'type' => 'LEFT',
                            'conditions' => array('DU.c_id = Ch.id AND MONTH( DU.created ) = MONTH( NOW( )')),
                       array(
                            'table' => 'd',
                            'alias' => 'D',
                            'type' => 'LEFT',
                            'conditions' => array('DU.c_id = Ch.id AND MONTH( DU.created ) = MONTH( NOW( )')),
    'group' => 'Ch.id');

我还没测试Cake JOINs的更多信息：

http://book.cakephp.org/view/1018/find

关于php - 使用find()方法查询cakePHP，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/5631524/