SELECT u.users_username, u.givenname, u.familyname, u.studentassent, u.parentconsent, u.birthdate, u.gender
FROM users AS u
JOIN classes_users as c
ON c.users_username = u.users_username
JOIN classes_users as x
ON c.classes_id = x.classes_id
WHERE x.users_username = "johnny" AND x.role = "teacher"

或者
SELECT u.users_username, u.givenname, u.familyname, u.studentassent, u.parentconsent, u.birthdate, u.gender
FROM users AS u
WHERE u.users_username
IN (
    SELECT c.users_username
    FROM classes_users as c
    JOIN classes_users as x
    ON c.classes_id = x.classes_id
    WHERE x.users_username = "johnny" AND x.role = "teacher"
)

我认为第一个更好,但我仍然在学习如何编写更好的SQL语句,在本例中,对于使一个语句优于另一个语句所发生的所有内部情况并不清楚。
如果有比我写的两种方法更好的方法,请告诉我。谢谢。
编辑:
有老师和学生。他们在任何一个班级中的学生或教师的地位可以通过查看classes_users表找到。我想做的是,当给一个用户,找到他是老师的班级,然后返回所有的学生在这些班级。
这是我的数据库架构:
-- -----------------------------------------------------
-- Table `kcptech`.`users`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `kcptech`.`users` (
`users_username` VARCHAR(63) NOT NULL ,
`password` VARCHAR(255) NULL DEFAULT NULL ,
`salt` VARCHAR(127) NULL DEFAULT NULL ,
`givenname` VARCHAR(96) NULL DEFAULT NULL ,
`familyname` VARCHAR(128) NULL DEFAULT NULL ,
`privileges` TINYINT NULL DEFAULT NULL ,
`studentassent` TINYINT(1) UNSIGNED NULL DEFAULT NULL ,
`parentconsent` TINYINT(1) UNSIGNED NULL DEFAULT NULL ,
`birthdate` DATE NULL DEFAULT NULL ,
`gender` VARCHAR(1) NULL DEFAULT NULL ,
`registration` TIMESTAMP NULL DEFAULT NULL ,
PRIMARY KEY (`users_username`) ,
UNIQUE INDEX `uname_UNIQUE` (`users_username` ASC) )
ENGINE = InnoDB;




-- -----------------------------------------------------
-- Table `kcptech`.`classes`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `kcptech`.`classes` (
`classes_id` INT UNSIGNED NOT NULL AUTO_INCREMENT ,
`course` VARCHAR(127) NULL ,
`period` VARCHAR(31) NULL DEFAULT '' ,
`organization` VARCHAR(127) NULL DEFAULT '' ,
PRIMARY KEY (`classes_id`) ,
UNIQUE INDEX `id_UNIQUE` (`classes_id` ASC) )
ENGINE = InnoDB;


-- -----------------------------------------------------
-- Table `kcptech`.`classes_users`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `kcptech`.`classes_users` (
`classes_id` INT UNSIGNED NOT NULL ,
`users_username` VARCHAR(64) NOT NULL ,
`role` VARCHAR(12) NOT NULL ,
PRIMARY KEY (`classes_id`, `users_username`) ,
INDEX `fk_class_users__users_users_username` (`users_username` ASC) ,
INDEX `fk_class_users__class_class_id` (`classes_id` ASC) ,
CONSTRAINT `fk_class_users__users_users_username`
  FOREIGN KEY (`users_username` )
  REFERENCES `kcptech`.`users` (`users_username` )
  ON DELETE NO ACTION
  ON UPDATE NO ACTION,
CONSTRAINT `fk_class_users__class_class_id`
  FOREIGN KEY (`classes_id` )
  REFERENCES `kcptech`.`classes` (`classes_id` )
  ON DELETE NO ACTION
  ON UPDATE NO ACTION)
ENGINE = InnoDB;

最佳答案

第一个更好,假设(classes_id, users_username)是唯一的。
MySQL不能使用内部查询前导进行半联接(IN构造)。因此IN查询将始终使用users作为前导表,而对于JOIN查询,优化器可以选择前导表。
如果(classes_id, users_username)不是唯一的,则查询在语义上是不等价的。您需要将DISTINCT添加到联接查询中。

10-08 09:10
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