我在Wildfly 10.1.0-Final上将Java EE 7与Java 8和Hibernate(5.0.X)结合使用,我需要使用投影将JPQL查询结果加载到DTO中,但是我找不到任何有关如何也加载子集合DTO。
例如,如果我具有以下用于用户,角色和权限的实体:
@Entity
public class User
{
@Id
private long id;
private String userName;
private String firstName;
private String lastName;
private JobTitle jobTitle;
private Email email;
private boolean isRemote;
@ManyToMany
private Set<Tag> tags;
@ManyToMany
// @JoinColumn definitions...
private Set<Role> roles;
// getters/setters...
}
@Entity
public class Role
{
@Id
private long id;
private String name;
private String description;
@ManyToMany
// @JoinColumn definitions...
private Set<Privilege> privileges;
// getters/setters...
}
@Entity
public class Privilege
{
@Id
private long id;
private String key;
private String name;
private String description;
// getters/setters...
}
我想使用投影将一些查询结果加载到以下不可变的DTO中(假设所有查询都具有hashCode并基于id实现equals):
public class UserDTO
{
private final long id;
private final String userName;
private final Set<RoleDTO> roles = new HashSet<>();
public UserDTO(long id, String userName, Collection<RoleDTO> roles) // not sure if this is correct for projection..
{
this.id = id;
this.userName = userName;
this.roles.addAll(roles);
}
public Set<Role> getRoles()
{
return Collections.unmodifiableSet(roles);
}
// getters
}
public class RoleDTO
{
private final long id;
private final String name;
private final Set<PrivilegeDTO> privileges = new HashSet<>();
public RoleDTO(long id, String name, Set<PrivilegeDTO> privileges)
{
this.id = id;
this.name = name;
this.privileges.addAll(privileges);
}
public Set<Privilege> getPrivileges()
{
return Collections.unmodifiableSet(privileges);
}
// other getters
}
public class PrivilegeDTO
{
private final long id;
private final String key;
public PrivilegeDTO(long id, String key)
{
this.id = id;
this.key = key;
}
// getters
}
JPQL查询的结构将如何实现这一目标?我很确定我可以通过执行联接,然后将结果处理到DTO对象中来完成工作,如下所示(按ID加载50个最新用户):
List<Object[]> results = em.createQuery("SELECT u.id, u.userName, r.id, "
+ "r.name, p.id, p.key FROM User u "
+ "LEFT JOIN u.roles r "
+ "LEFT JOIN r.privileges p "
+ "ORDER BY u.id DESC")
.setMaxResults(50).getResultList();
Map<Long, UserDTO> users = new HashMap<>();
Map<Long, RoleDTO> roles = new HashMap<>();
Map<Long, PrivilegeDTO> privileges = new HashMap<>();
for(Object[] objArray : results)
{
// process these into the DTO objects,
}
重建必须从PrivilegeDTO对象开始,然后是RoleDTO,最后是UserDTO。这将实现不可变性,因为在构建RoleDTO对象时需要使用PrivilegeDTO对象,或者以后必须添加它们,这意味着RoleDTO并非不可变的。
这在Streams中是一个有趣的练习,但是我更希望能够仅通过查询来构建它,这似乎必须更快。那有可能吗?
非常感谢!
最佳答案
嗨,摩根,简短的回答是不,您无法从查询中构建内容,因为您无法将JPQL映射到DTO集合字段。这是一个与JPQL: Receiving a Collection in a Constructor Expression有关的问题
无论如何,您可以使用Spel https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query.spel-expressions尝试使用Spring投影的方法
但我认为正确的解决方案是使用手动映射,如本答案https://stackoverflow.com/a/45934668/3449039中所述