我有以下课程

public class CountrySpecificPIIEntity
{
    public string Country { get; set; }
    public string CreditCardType { get; set; }
    public String Language { get; set; }
    public List<String> PIIData { get; set; }
}


我有以下要使用Linq-to-xml查询的XML,并在上面的类中成形

            <?xml version="1.0" encoding="utf-8" ?>
            <piisettings>
              <piifilter country="DE" creditcardype="37" language="ALL" >
                <filters>
                  <filter>FIRSTNAME</filter>
                  <filter>SURNAME</filter>
                  <filter>STREET</filter>
                  <filter>ADDITIONALADDRESSINFO</filter>
                  <filter>ZIP</filter>
                  <filter>CITY</filter>
                  <filter>STATE</filter>
                  <filter>EMAIL</filter>
                </filters>
              </piifilter>
              <piifilter country="DE" creditcardype="37" Language="en" >
                <filters>
                  <filter>EMAIL</filter>
                </filters>
              </piifilter>
            </piisettings>


我正在使用以下查询,但是在最后一个属性(即PIIList)上遇到了麻烦。

            var query = from pii in xmlDoc.Descendants("piifilter")
            select new CountrySpecificPIIEntity
            {
               Country = pii.Attribut("country").Value,
               CreditCardType = pii.Attribute("creditcardype").Value,
               Language = pii.Attribute("Language").Value,
               PIIList = (List<string>)pii.Elements("filters")
            };

            foreach (var entity in query)
            {
            Debug.Write(entity.Country);
            Debug.Write(entity.CreditCardType);
            Debug.Write(entity.Language);
            Debug.Write(entity.PIIList);
            }


如何获取查询以将要合并的列表返回到PIIList属性。

最佳答案

var query = from pii in xmlDoc.Descendants("piifilter")
select new CountrySpecificPIIEntity
{
   Country = pii.Attribut("country").Value,
   CreditCardType = pii.Attribute("creditcardype").Value,
   Language = pii.Attribute("Language").Value,
   PIIList = pii.Elements("filters").Select(xe => xe.Value).ToList();
};

07-28 01:37
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