出现模式弹出窗口时,如何暂停保存数据的处理?
当我单击该模式弹出窗口中的按钮时,保存数据的执行将继续进行。
我的Modal弹出窗口的作用就像一个消息框...
这是我的示例代码:
bool overlap= false;
foreach (ListItem item in chkMBoxEmployeeList.Items)
{
if (overlap == true)
{
//Saving of data
}
else if (overlap == false)
{
ModalpopupExtender2.Show();
//In this condition, I will pause the execution of saving the data
}
}
//I used this after the ModalpopupExtender2.Show():
return;
//but I think, this will not be the answer, because my code will become very long if use that. I will rewrite again my code in the button in modalpopup if I use that.
我应该使用线程吗? 线程在ASP.Net上工作吗?
最佳答案
您的保存过程在服务器上进行,但是模态对话框将显示在客户端上。您不能使服务器等待浏览器中的用户响应。相反,服务器处理必须结束并将修改后的页面发送到浏览器。现在,浏览器将再次提交所有数据以及确认信息。由于您使用的是ASP.NET WebForms,您会很幸运,因为它可以自动处理这种情况下的状态。
public void Save(bool confirmed)
{
if (!confirmed && NeedsConfirmation())
{
ShowModalWindow();
return;
}
// here perform the operation.
}
public void ButtonSave_Click(object sender, EventArgs e)
{
// this is the button that is normally displayed on the form
this.Save(false);
}
public void ButtonConfirm_Click(object sender, EventArgs e)
{
// this button is located within the modal dialog - so it is not shown before that.
this.Save(true);
}
关于c# - 模态弹出框显示时暂停保存数据的处理,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/14518628/