c - 如何使用结构？

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How do we use structs?
                                
                                    （2个答案）
                                
                        
                                5年前关闭。
            
                    
提出一个新问题，导致我的旧问题在花了很长时间进行编辑后才去世。
因此，我试图摆脱这段代码中的所有这些参数（是的，某些参数是多余的，但我只是以防万一）添加了它们：

#include <stdio.h>

int main()
{
    //Top coord. of the square
    int top_x1 = 0;
    int top_y1 = 10;
    int top_x2 = 10;
    int top_y2 = 10;

    //Bottom coord. of the square
    int bottom_x1 = 0;
    int bottom_y1 = 0;
    int bottom_x2 = 10;
    int bottom_y2 = 0;

    //Left coord. of the square
    int left_x1 = 0;
    int left_y1 = 0;
    int left_x2 = 0;
    int left_y2 = 10;

    //Right coord. of the square
    int right_x1 = 10;
    int right_y1 = 0;
    int right_x2 = 10;
    int right_y2 = 10;

    parameter(top_x1, top_y1, top_x2, top_y2, bottom_x1,
              bottom_y1, bottom_x2, bottom_y2, left_x1,
              left_y1, left_x2, left_y2, right_x1, right_y1,
              right_x2, right_y2);
}

parameter (int top_x1,int top_y1,int top_x2,int top_y2,int bottom_x1,
              int bottom_y1,int bottom_x2,int bottom_y2,int left_x1,
              int left_y1,int left_x2,int left_y2,int right_x1,int right_y1,
              int right_x2,int right_y2)
{
    int totalParameter, topSide, bottomSide, leftSide, rightSide;

    topSide = (top_x2 - top_x1);
    bottomSide = (bottom_x2 - bottom_x1);
    leftSide = (left_y2 - left_y1);
    rightSide = (right_y2 - right_y1);

    totalParameter = (topSide + bottomSide + leftSide + rightSide);
    printf("%d\n", totalParameter);

}

工作完美，但参数太多！如果我尝试使用结构...

#include <stdio.h>>

struct coordinates
{
    int x1, y1, x2, y2;
};

int main()
{
    struct coordinates top;
    struct coordinates bottom;
    struct coordinates left;
    struct coordinates right;

    //Top line of the square
    top.x1 = 0;
    top.y1 = 10;
    top.x2 = 10;
    top.y2 = 10;

    //Bottom line of the square
    bottom.x1 = 0;
    bottom.y1 = 0;
    bottom.x2 = 10;
    bottom.y2 = 0;

    //Left line of the square
    left.x1 = 0;
    left.y1 = 0;
    left.x2 = 0;
    left.y2 = 10;

    //Right line of the square
    right.x1 = 10;
    right.y1 = 0;
    right.x2 = 10;
    right.y2 = 10;

    parameter(top,bottom,left,right);
}

parameter(top, bottom, left, right)
{
    int totalParameter, topSide, bottomSide, leftSide, rightSide;

    topSide = (top.x2 - top.x1);
    bottomSide = (bottom.x2 - bottom.x1);
    leftSide = (left.y2 - left.y1);
    rightSide = (right.y2 - right.y1);

    totalParameter = topSide + bottomSide + leftSide + rightSide;
    printf("%d\n", totalParameter);

}

我希望它打印出来：40。

不过不行，请帮忙吗？
我得到的错误是：“在非联合结构中请求成员'x1'。
对于所有x和y坐标。

最佳答案

该函数需要定义其返回类型和定义其参数的类型，如下所示：

void parameter(struct coordinates top, struct coordinates bottom, struct coordinates left, struct coordinates right)

如果不这样做，则参数默认为键入int（这比C语言更重要的是C中的历史课程）。如果您也没有预先声明函数，那么它就是implicitly declared（在现代C语言中是非法的），并假设您的参数和函数类型与应有的不同（它们均默认为int类型）。