我正在借助模板以特定的方式调用API,但在传递常量参数方面留下了一个问题。

我的尝试与诠释:

    template <typename F, typename ...Ts>
          static int f3(int bound, CString file, int line, CString Caller,
                        CString f_name, F f, Ts&& ...ts) {
                 int err = fn(bound, file, line, Caller, f_name,
                 f, std::tuple<Ts...>(ts...), seq3<bound>{},  // error C2975
                 seq1<sizeof...(Ts)>{});
                 return err;
    }


在主要方面:

int const bound;
bound = 4;

err = fn(bound, api(GetModuleFileName), rval, nullptr, path, MAX_PATH, L"EXE-path");

compiler error C2975: 'N': invalid template argument for 'seq3', expected compile-time constant expression


如何解决这个问题?

我现在的解决方法:

err = f3(api(GetModuleFileName),rval,nullptr,path,MAX_PATH,L“ EXE-path”);

f3是具有3个参数的API的专门化,因为到目前为止,我无法传递上限(在这种情况下为4)以生成序列:。
调用具有3个参数的API需要此序列,其中tupel从f3()中的参数rval开始。

背景:

api是#define

f3调用API。

f3在序列/ tuple的0位置处理API的返回值。

f3使用所有参数调用另一个可变参数函数来记录调试信息。

一个tupel和两个序列用于两个函数调用。

问题:

我想传递一个参数来控制不是由tupel-size而是由API函数签名给出的序列的上限。

对于所有API,我只需要一个fn(),对于参数为0、1、2、3 ...的API,则不希望使用f0(),f1(),f2(),f3()........。

我想要这样的东西:

err = fn(seq3 ,api(GetModuleFileName),rval,nullptr,path,MAX_PATH,L“ EXE-path”)

这是我的工作代码:

#include <windows.h>
#include <atlstr.h>
#include <tuple>
#include <utility>

template <int ... Ns> struct seq_3 {};
template <int ... Ns> struct seq3_n {};

template <int I, int ... Ns> struct seq3_n<I, Ns...>{
   using type = typename seq3_n<I - 1, I - 1, Ns...>::type;};

template <int ... Ns> struct seq3_n<1, Ns...>{
// skip first argument : rval, because it doesn't fit to API,
// but needed for calling other function
   using type = seq_3<Ns...>;                };

template <int N>
   using seq3 = typename seq3_n<N>::type;

template <int ... Ms> struct seq_1 {};
template <int ... Ms> struct seq1_n {};
template <int J, int ... Ms> struct seq1_n<J, Ms...>{
   using type = typename seq1_n<J - 1, J - 1, Ms...>::type; };
template <int ... Ms> struct seq1_n<0, Ms...> {
   using type = seq_1<Ms...>;                };
template <int M>
   using seq1 = typename seq1_n<M>::type;

template <typename F, typename TUP, int ... INDICES3, int ... INDICES1>
   static int fn(CString file,  int line, CString Caller, CString f_name,
              F f, TUP tup, seq_3<INDICES3...>, seq_1<INDICES1...>) {
                int err = 0;
                // handling of rval = first element of tuple
                std::get<0>(tup) = f(std::get<INDICES3>(tup) ...);  // calling API
                err = GetLastError();
                /* calling next function (variadic too) with same tupel, but other sequence
                 myOpenDebugOutputString(project, file, line, Caller, f_name, std::get<INDICES1>(tup) ..., "stop");
                */
                return err; }

template <typename F, typename ...Ts>
   static int f3(CString file, int line, CString Caller, CString f_name,
              F f, Ts&& ...ts)  {
                int err = fn(file, line, Caller, f_name,
                f, std::tuple<Ts...>(ts...), seq3<4>{},  // sequence fixed by f3
                seq1<sizeof...(Ts)>{});                  // 3 arguments api  + skip 1 rval = 4
                return err;                              // given by signature of API
}


int main() {
    // for calling simple API GetModulFileName with 3 arguments
    //                                      returns len(path)
    wchar_t     path[MAX_PATH];
    DWORD           rval = 0;
    int         err = 0;
    rval = GetModuleFileName( nullptr, path, MAX_PATH);
    err  = GetLastError();

#define api(a)  __FILE__, __LINE__, __func__, L#a, a
// L#a becomes L"GetModuleFileName"

    err = f3(api(GetModuleFileName), rval, nullptr, path, MAX_PATH, L"EXE-path");

    return 0; }


提前致谢。

附言
我正在使用Microsoft Visual Studio 2015

更新:

我在Richard Hodges解决方案的模板api_call中尝试了以下操作。

std::tuple<GivenArgs...> tup(args...);

// OK, but only for an api with 3 arguments
callsite.function(std::get<0>(tup), std::get<1>(tup), std::get<2>(tup));

// compiler error too many arguments
callsite.function(std::forward<GivenArgs>(args)..., seq1<callsite.nofArgs()>{});

// compiler error too few arguments
callsite.function(tup, seq1<callsite.nofArgs()>{});


备注:

seq1 = seq_1

callsite.nofArg()= 3


  如何获得正确数量的参数?

最佳答案

尚不清楚您要如何处理错误等。我假设返回错误代码和值的元组。

这是一种一般模式,我认为它将满足您的要求。您需要注意emit_log的特殊化和重载,尤其是对于不能以null终止或包含非打印字符的字节数组。

为了方便起见,我使用了窄字符,但是这个想法可以在进行一些编辑的宽字符中使用。

注意:在linux gcc上进行了编辑,因此我模拟了Windows API。

#include <cstdint>
#include <utility>
#include <iostream>
#include <variant>

#define WINAPI
#define _In_opt_
#define _Out_
#define _In_

struct _hmodule {};
using HMODULE = _hmodule*;
using LPTSTR = char*;
using LPCTSTR = const char*;
using DWORD = std::uint32_t;

extern DWORD WINAPI GetModuleFileName(
  _In_opt_ HMODULE hModule,
  _Out_    LPTSTR  lpFilename,
  _In_     DWORD   nSize
);

extern WINAPI DWORD GetLastError();

template<class Ret, class...Args>
struct api_call_site
{
    const char* file;
    int line;
    const char* current_function;
    const char* called_function;
    Ret (* function)(Args...);
};

template<class Ret, class...Args>
auto make_api_call_site(const char* file, int line, const char* callername, const char* calleename, Ret (* WINAPI callee)(Args...))
{
    return api_call_site<Ret, Args...>
    {
        file,
        line,
        callername,
        calleename,
        callee
    };
}

template<class T>
void emit_log(LPCTSTR& sep, std::ostream& os, T&& x)
{
    os << sep << x;
    sep = ",";
}

template<class Ret>
struct error_with_value
{
    DWORD error;
    Ret value;

    bool has_error() const { return error != 0; }
    friend std::ostream& operator<<(std::ostream& os, const error_with_value& ewv)
    {
        os << "{ error: " << ewv.error << ", value: ";
        LPCTSTR sep = "";
        emit_log(sep, os, ewv.value);
        os << " }";
        return os;
    }
};


#define api(a) make_api_call_site(__FILE__, __LINE__, __func__, #a, a)


// this will need some specialisations...
void emit_log(LPCTSTR& sep, std::ostream& os, std::nullptr_t)
{
    os << sep << "nullptr";
    sep = ",";
}

template<class Ret, class...Args, class...GivenArgs>
auto api_call(api_call_site<Ret, Args...> const& callsite, GivenArgs&&...args) -> error_with_value<Ret>
{
    // log call here
    std::clog << callsite.file << ":" << callsite.line << "@" << callsite.current_function << " - ";
    std::clog << "calling " << callsite.called_function << "(";
    // appropriate code to print arguments in a safe way here...
    LPCTSTR sep = "";
    using expand = int[];
    void(expand{0,
        (emit_log(sep, std::clog, args),0)...
    });
    std::clog << ")";
    error_with_value<Ret> result
    {
        0,
        callsite.function(std::forward<GivenArgs>(args)...)
    };
    result.error = GetLastError();

    std::clog << " -> returns: " << result;
    return result;
}

int main()
{
    char buffer[255];
    DWORD bufsize = 255;

    auto result = api_call(api(GetModuleFileName), nullptr, buffer, bufsize);
    if (! result.has_error())
    {
        //
    }

}


示例输出:

main.cpp:120@main - calling GetModuleFileName(nullptr,,255) -> returns: { error: 0, value: 14 }


http://coliru.stacked-crooked.com/a/e5da55af212d5500


  如何获取API调用中的参数数量?


template<class Ret, class...Args>
struct api_call_site
{
    const char* file;
    int line;
    const char* current_function;
    const char* called_function;
    Ret (* function)(Args...);

    // like this
    static constexpr std::size_t nofArgs()
    {
        return sizeof...(Args);
    }
};

关于c++ - C++将序列上限传递给可变参数函数模板,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/46503560/

10-11 22:59
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