#include<iostream>

using namespace std;

template <class T>
void myswap(T & tmp1, T & tmp2)
{
    T temp;
    temp = tmp1;
    tmp1 = tmp2;
    tmp2 = temp;
    return;
}

main()
{
    int x = 1;
    int y = 20;
    double p = 10.9, q = 23.36;
    char s = 'o', t = 'u';

    myswap(x, y);
    cout << "x=" << x << "and y=" << y << endl;

    myswap(p, q);
    cout << "p=" << p<< "and q=" << q << endl;

    myswap(s, t);
    cout << "s=" << s << "and t=" << t << endl;

    return 0;
}

我使用Visual Studio2013。运行此代码时,编译器会向我显示消息“错误:缺少类型说明符-假定为int。C++不支持默认int”。

最佳答案

函数main必须具有返回类型int,即

int main()

关于c++ - 错误1错误C4430 : missing type specifier - int assumed. Note: C++ does not support default-int,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20250792/

10-11 22:40
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