我已经有一段时间没有接触过c++了,在通过引用传递2D vector 时,我刚遇到一个非常奇怪的问题,它在main
函数中进行了描述:
class Solution {
public:
vector<vector<int> > permute(vector<int> &num) {
vector<vector<int> > result;
//I intentionally omit the codes for permutation,
//only pushing the original one to the result
result.push_back(num);
return result;
}
//print the permutation, I want to pass by referrence
void printPerm(vector<vector<int> > &result) {
for(int i=0; i<result.size(); i++) {
for(int j=0; j<result[i].size(); j++) {
cout << result[i][j]<<" ";
}
}
}
};
int main() {
vector<int> old;
old.push_back(1);
old.push_back(2);
old.push_back(3);
Solution sol;
//this gives me error for no matching function
//call, candidate argument doesn't match
sol.printPerm((sol.permute(old)));
//but the one below works!
vector<vector<int> > result = sol.permute(old);
sol.printPerm(result);
}
最佳答案
您需要添加const
作为结果以允许绑定(bind)到右值
void printPerm(const vector<vector<int> > &result)
// ^^^^^^