我是使用Moq进行测试的新手,所以对ReturnsAsync
感到有些困惑。
这是我的测试方法,我希望ReturnsAsync
应该收到将由Setup
中定义的方法返回的类型。我对吗?
但是似乎ReturnsAsync
应该具有其他签名-它正在寻找Func
委托。
[TestClass]
public class TourObjectControllerTest
{
[TestMethod]
public async Task GetTourObjects()
{
var mockService = new Mock<ITourObjectService>(MockBehavior.Default);
mockService.Setup(x => x.GetAll()).ReturnsAsync(new Task<IEnumerable<TourObjectDTO>>);
var controller = new TourObjectController(mockService.Object);
var result = await controller.Get();
Assert.IsNotNull(result);
Assert.AreSame(typeof(TourObjectViewModel), result);
}
}
被测方法:
public async Task<IEnumerable<TourObjectViewModel>> Get()
{
IEnumerable<TourObjectViewModel> viewmodel = null;
try
{
var tourobjects = await _tos.GetAll();
viewmodel = Mapper.Map<IEnumerable<TourObjectViewModel>>(tourobjects);
}
catch (Exception ex)
{
Log.ErrorFormat("Method:{0} <br/> Error: {1}", System.Reflection.MethodBase.GetCurrentMethod().Name, ex);
}
return viewmodel;
}
最佳答案
通过实际结果。
假设ITourObjectService.GetAll()
返回Task<IEnumerable<TourObjectDTO>>
例如
[TestClass]
public class TourObjectControllerTest
{
[TestMethod]
public async Task GetTourObjects()
{
var fakeData = new List<TourObjectDTO>() {
new TourObjectDTO { ... }
};
var mockService = new Mock<ITourObjectService>(MockBehavior.Default);
mockService.Setup(x => x.GetAll()).ReturnsAsync(fakeData);
var controller = new TourObjectController(mockService.Object);
var result = await controller.Get();
Assert.IsNotNull(result);
Assert.IsTry(typeof(IEnumerable<TourObjectViewModel>).IsAssignableFrom(result.GetType());
}
}
关于c# - Moq Web Api异步方法,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/41042255/