输入JSON文件:
{
"@version": "2.7.0",
"@generated": "Wed, 30 May 2018 17:23:14",
"site": {
"@name": "http://google.com",
"@host": "google.com",
"@port": "80",
"@ssl": "false",
"alerts": [
{
"alert": "X-Content-Type-Options Header Missing",
"name": "X-Content-Type-Options Header Missing",
"riskcode": "1",
"confidence": "2",
"riskdesc": "Low (Medium)",
"desc": "<p>The Anti-MIME-Sniffing header X-Content-Type-Options was not set to 'nosniff'. This allows older versions of Internet Explorer and Chrome to perform MIME-sniffing on the response body, potentially causing the response body to be interpreted and displayed as a content type other than the declared content type. Current (early 2014) and legacy versions of Firefox will use the declared content type (if one is set), rather than performing MIME-sniffing.</p>",
"instances": [
{
"uri": "http://google.com",
"method": "GET",
"param": "X-Content-Type-Options"
}
],
"wascid": "15",
"sourceid": "3"
}
]
}
}
预期产量:
列出警报;
哪里:
public class Alert
{
public string alert;
public string riskcode;
}
我想获取json对象的特定键,然后在警报对象中反序列化它。
最佳答案
最简单的方法是仅使用足够的键声明外部对象以达到您关心的键:
public class Alert
{
public string alert;
public string riskcode;
}
public class SiteAlerts
{
public Site site { get; set; }
}
public class Site
{
public List<Alert> alerts { get; } = new List<Alert>();
}
然后,您可以简单地反序列化:
var siteAlerts = JsonConvert.DeserializeObject<SiteAlerts>(json);
var alerts = siteAlerts.site.alerts; // no error-checking here