因此,我已经调试了这个超长查询。我最初收到的错误是s.name列和所有其他JOIN列不在“字段列表”中,因此经过一番谷歌搜索后,我能够通过将它们放在双引号中来解决该错误。因此,现在查询返回的资源没有错误,但是资源为空。
现在,我在语句后从回声中得到的是“资源ID#4警告:implode():无效的参数在第143 0行的/var/www/beta/index.php中传递”
这是查询和周围的功能:
<?php /* other functions preceding */ $result = mysql_query("SELECT * FROM users WHERE uid=" . $_SESSION['uid'] . "");
$cur_user = mysql_fetch_array($result);
$ufriends = explode(';', $cur_user['friends']);
$ufsql = trim(implode(',',$ufriends),',');
$uevents = explode(';', $cur_user['events']);
$uesql = trim(implode(',',$uevents),',');
$urequests = explode(';', $cur_user['requests']);
$ursql = trim(implode(',',$urequests),',');
if (!empty($ufriends)) {
$time1 = microtime();
$megaresult = mysql_query("
( SELECT \"s.name\" AS source_name, NULL AS target_name, recent_updates.*, 1 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
WHERE update_type='10'
LIMIT 1
)
UNION
( SELECT \"s.name\" AS source_name, NULL AS target_name, recent_updates.*, 2 as ORD FROM recent_updates
INNER JOIN users AS su ON (\"s.uid\"=recent_updates.source_id)
WHERE update_type='10'
LIMIT 1,9
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN users AS t ON (\"t.uid\"=recent_updates.target_id)
WHERE update_type='2'
AND
( target_id IN (" . $ufsql . ") )
AND
( source_id IN (" . $ufsql . ") )
OR
(
( target_id IN (" . $cur_user['uid'] . ") )
AND
( source_id IN (" . $ufsql . ") )
)
OR
(
( target_id IN (" . $ufsql . ") )
AND
( source_id IN (" . $cur_user['uid'] . ") )
)
LIMIT 0,10
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN users AS t ON (\"t.uid\"=recent_updates.target_id)
WHERE update_type='4'
AND
(
( target_id IN (" . $ufsql . ") )
AND
( source_id IN (" . $ufsql . ") )
)
OR
(
( target_id IN (" . $cur_user['uid'] . ") )
AND
( source_id IN (" . $ufsql . ") )
)
OR
(
( target_id IN (" . $ufsql . ") )
AND
( source_id IN (" . $cur_user['uid'] . ") )
)
LIMIT 0,10
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN events AS t ON (\"t.id\"=recent_updates.target_id)
WHERE update_type='3'
AND
target_id IN (" . $uesql . ")
LIMIT 0,10
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN events AS t ON (\"t.id\"=recent_updates.target_id)
WHERE update_type='3'
AND
target_id IN (" . $ursql . ")
LIMIT 0,10
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN events AS t ON (\"t.id\"=recent_updates.target_id)
WHERE update_type='5'
AND
target_id IN (" . $ursql . ")
LIMIT 0,10
)
UNION
( SELECT \"s.name\" AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN users AS s ON (\"s.uid\"=recent_updates.source_id)
INNER JOIN events AS t ON (\"t.id\"=recent_updates.target_id)
WHERE update_type='11'
AND
(
target_id IN (" . $uesql . ")
OR
target_id IN (" . $ursql . ")
)
AND
(
source_id IN (" . $ufsql . ")
)
LIMIT 0,10
)
UNION
( SELECT NULL AS source_name, \"t.name\" AS target_name, recent_updates.*, 2 AS ORD FROM recent_updates
INNER JOIN events AS t ON (\"t.id\"=recent_updates.target_id)
WHERE public != 0 LIMIT 0,10
)
ORDER BY ORD ASC, time_un DESC");
echo $megaresult;
$feed = mysql_fetch_array($megaresult);
echo mysql_error();
$time2 = microtime();
echo implode('##', $feed);
echo mysql_num_rows($megaresult);
echo mysql_info($con);
/* brackets closed, etc */ ?>
我觉得这与将别名列放在双引号中有关。我有此查询的先前版本,其中不包含任何运行正常的JOIN部分,我将其上传到pastebin:http://pastebin.com/upifa7VJ
编辑:
好吧,这令人尴尬...我正确地怀疑引号是引起问题的原因(感谢@andrewtweber!),但是我没有引号的错误是由于第二个SELECT语句中的错字,INNER JOIN users AS su代替INNER JOIN用户。感谢大家的帮助!
最佳答案
双引号表示您选择的是字符串“ s.name”,而不是列s.name
。
您可能想做的是使用反引号`。反引号允许您将保留的MySQL关键字用作列名,例如
SELECT `table`.`name` FROM `table` ORDER BY `order` ASC
关于php - MySQL查询返回无效资源但没有错误,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/11275643/