我有一个包含不同对象的数组,其中每个对象都是一个订单。
看起来像这样:
array = [
{
doc : {
date: "2017-03-06T16:48:23.080Z",
products:[
{
product: "Product 1",
number: 3
},
{
product: "Product 2",
number: 2
}
]
}
},
{
doc : {
date: "2017-03-07T16:48:23.080Z",
products:[
{
product: "Product 2",
number: 10
},
{
product: "Product 3",
number: 1
}
]
}
}
]
我希望能够获取这些数据并将其推入新的数组,每个数组都有一个date属性(按日期分组)和一个产品嵌套的数组,该数组将不同的订单分组(按产品分组)。像这样:
array = [
{
date: 'Date X',
products: [
{
product: 'product 1',
units: 3
},
{
product: 'product 2',
units: 2
}
]
},
{
date: 'Date Y',
products: [
{
product: 'product 2',
units: 10
},
{
product: 'product 3',
units: 1
}
]
}
]
您将如何处理?到目前为止,我已经尝试过与Lodash尝试重用一些旧代码,但运气不好。可以用forEach完成吗?
最佳答案
使用lodash和ES6的解决方案:
// Remove unnecesary .doc properties
let arrayWithoutDoc = _.map(array, el => el.doc);
// Group by dates to single object
let grouped = _.groupBy(arrayWithoutDoc, el => el.date);
// Convert object to requested format
let result = _.map(grouped, (value, date) => ({
date: date,
products: sumProductsUnits(
_.flatMap(value, el => el.products)
)
}));
// Function for grouping unique products with sum of units
function sumProductsUnits(products) {
var productGroups = _.groupBy(products, productObj => productObj.product);
return _.map(productGroups, (productGroup, productName) => ({
product: productName,
units: productGroup.reduce((sum, val) => sum + val.number, 0)
}))
}
我假设在原始对象中
units
等于number
。result
包含:[
{
"date":"2017-03-06T16:48:23.080Z",
"products":[
{
"product":"Product 1",
"units":3
},
{
"product":"Product 2",
"units":2
}
]
},
{
"date":"2017-03-07T16:48:23.080Z",
"products":[
{
"product":"Product 2",
"units":10
},
{
"product":"Product 3",
"units":1
}
]
}
]
关于javascript - 分组数组中的数据,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/42610343/