假设我有一个这样的数组:
let games = [
Game(type: "Soccer", value: 1),
Game(type: "Basket", value: 3),
Game(type: "Hockey", value: 5),
Game(type: "Soccer", value: 2),
Game(type: "Soccer", value: 4),
Game(type: "Basket", value: 2)
]
我想要一个新的数组,每种类型有一行,并用匹配的类型互相添加值。像这样的:
let newGames = [
NewGame(type: "Soccer", value: 7),
NewGame(type: "Basket", value: 5),
NewGame(type: "Hockey", value: 5)
]
请帮忙。我的大脑不合作。
最佳答案
struct Game {
let type: String
let value: Int
}
let games: [Game] = [
Game(type: "Soccer", value: 1),
Game(type: "Basket", value: 3),
Game(type: "Hockey", value: 5),
Game(type: "Soccer", value: 2),
Game(type: "Soccer", value: 4),
Game(type: "Basket", value: 2)
]
var totalValueForGame = [String: Int]()
for game in games {
totalValueForGame[game.type] = game.value + (totalValueForGame[game.type] ?? 0)
}
let newGames = totalValueForGame.map { Game(type: $0, value: $1) }
print(newGames)
输出:
[Game(type: "Soccer", value: 7), Game(type: "Hockey", value: 5), Game(type: "Basket", value: 5)]
关于arrays - Swift:数组中重复字符串时值之间的加法,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33486251/