我想将php数组转换为json字符串，以与JavaScript InfoVis Toolkit formart一起使用。
目的：
InfoVis Demo Tree
Json规范格式：
InfoVis-loading and serving JSON data
我有这个php数组：$ my_array：
Array
(
[item_1] => Array
(
[id] => item_1_ID
[name] => item_1_NAME
[data] => item_1_DATA
[children] => Array
(
[door] => Array
(
[id] => door_ID
[name] => door_NAME
[data] => door_DATA
[children] => Array
(
[mozart] => Array
(
[id] => mozart_ID
[name] => mozart_NAME
[data] => mozart_DATA
[children] => Array
(
[grass] => Array
(
[id] => grass_ID
[name] => grass_NAME
[data] => yes
)
[green] => Array
(
[id] => green_ID
[name] => green_NAME
[data] => no
)
[human] => Array
(
[id] => human_ID
[name] => human_NAME
[data] => human_DATA
[children] => Array
(
[blue] => Array
(
[id] => blue_ID
[name] => blue_NAME
[data] => blue_DATA
[children] => Array
(
[movie] => Array
(
[id] => movie_ID
[name] => movie_NAME
[data] => yes
)
)
)
)
)
)
)
)
)
[beat] => Array
(
[id] => beat_ID
[name] => beat_NAME
[data] => yes
)
[music] => Array
(
[id] => music_ID
[name] => music_NAME
[data] => no
)
)
)
)
现在如果我json_encode（$ my_array）;
{
"item_1": {
"id": "item_1_ID",
"name": "item_1_NAME",
"data": "item_1_DATA",
"children": {
"door": {
"id": "door_ID",
"name": "door_NAME",
"data": "door_DATA",
"children": {
"mozart": {
"id": "mozart_ID",
"name": "mozart_NAME",
"data": "mozart_DATA",
"children": {
"grass": {
"id": "grass_ID",
"name": "grass_NAME",
"data": "yes"
},
"green": {
"id": "green_ID",
"name": "green_NAME",
"data": "no"
},
"human": {
"id": "human_ID",
"name": "human_NAME",
"data": "human_DATA",
"children": {
"blue": {
"id": "blue_ID",
"name": "blue_NAME",
"data": "blue_DATA",
"children": {
"movie": {
"id": "movie_ID",
"name": "movie_NAME",
"data": "yes"
}
}
}
}
}
}
}
}
},
"beat": {
"id": "beat_ID",
"name": "beat_NAME",
"data": "yes"
},
"music": {
"id": "music_ID",
"name": "music_NAME",
"data": "no"
}
}
}
}
但是对于InfoVis，当前的json输出（json_encode（$ my_array））有3个问题：
没有使用[]
'children'数组具有键名
数组项具有其键名->示例：“ item_1”：{...。
让我指出问题所在，以便也许您可以提供函数来转换此json字符串：
看到这片json_encode（$ my_array）输出：
{
"item_1": {
"id": "item_1_ID",
"name": "item_1_NAME",
"data": "item_1_DATA",
"children": {
"door": {
"id": "door_ID",
1.问题1：
{
"item_1": {
我们必须删除以下键：“ item_1”：
2.问题2：
"children": {
"door": {
"id": "door_ID",
正确的代码应为：
"children": [
{
"id": "door_ID",......
“门”：已删除...因为它是钥匙
“孩子”：{=>变为““孩子”：[
“孩子”的工作示例：
"children": [
{
"id": "grass_ID",
"name": "grass_NAME",
"data": "yes"
},
{
"id": "green_ID",
"name": "green_NAME",
"data": "no"
}
]
阐明WORKING Json InfoVis格式的完整示例：
json = {
id: "node02",
name: "0.2",
children: [{
id: "node13",
name: "1.3",
children: [{
id: "node24",
name: "2.4"
}, {
id: "node222",
name: "2.22"
}]
}, {
id: "node125",
name: "1.25",
children: [{
id: "node226",
name: "2.26"
}, {
id: "node237",
name: "2.37"
}, {
id: "node258",
name: "2.58"
}]
}, {
id: "node165",
name: "1.65",
children: [{
id: "node266",
name: "2.66"
}, {
id: "node283",
name: "2.83"
}, {
id: "node2104",
name: "2.104"
}, {
id: "node2109",
name: "2.109"
}, {
id: "node2125",
name: "2.125"
}]
}, {
id: "node1130",
name: "1.130",
children: [{
id: "node2131",
name: "2.131"
}, {
id: "node2138",
name: "2.138"
}]
}]
};
明白了吗？
希望任何人都可以帮助我..我已经为此工作了好几天！
谢谢。
最佳答案
试试这个快速转换功能
function fixit($yourArray) {
$myArray = array();
foreach ($yourArray as $itemKey => $itemObj) {
$item = array();
foreach ($itemObj as $key => $value) {
if (strtolower($key) == 'children') {
$item[$key] = fixit($value);
} else {
$item[$key] = $value;
}
}
$myArray[] = $item;
}
return $myArray;
}
$fixed = fixit($my_array);
$json = json_encode($fixed);
关于php - PHP数组转换为Json树格式，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/8730577/