我有一个如下的Javascript对象数组。
[{
"email": "alex@test.com",
"fn": "Alex",
"sn": "McPherson",
"phone": "01233xxxxx",
"hours": "40",
"rate": "20",
"amount": "200",
"vat": "60",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
},
{
"email": "mike@test.com",
"fn": "Mike",
"sn": "Mann",
"phone": "01233xxxxx",
"hours": "50",
"rate": "70",
"amount": "500",
"vat": "90",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
},
{
"email": "fred@test.com",
"fn": "Fred",
"sn": "Frogg",
"phone": "01233xxxxx",
"hours": "80",
"rate": "90",
"amount": "800",
"vat": "100",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
},
{
"email": "alex@test.com",
"fn": "Alex",
"sn": "McPherson",
"phone": "01233xxxxx",
"hours": "90",
"rate": "30",
"amount": "900",
"vat": "120",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
}]
我理想的情况是将具有相同值（电子邮件）的对象分组到自己的子对象数组中，即，如果您查看上面的数组，您将看到我为同一个人Alex McPherson有2个条目。我想做的是在可能的情况下移动并组合到一个子数组中，对于存在多个以上的任何其他值，则要这样做。
[[{
"email": "alex@test.com",
"fn": "Alex",
"sn": "McPherson",
"phone": "01233xxxxx",
"hours": "40",
"rate": "20",
"amount": "200",
"vat": "60",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
},{
"email": "alex@test.com",
"fn": "Alex",
"sn": "McPherson",
"phone": "01233xxxxx",
"hours": "90",
"rate": "30",
"amount": "900",
"vat": "120",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
}],
[{
"email": "mike@test.com",
"fn": "Mike",
"sn": "Mann",
"phone": "01233xxxxx",
"hours": "50",
"rate": "70",
"amount": "500",
"vat": "90",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
}],
[{
"email": "fred@test.com",
"fn": "Fred",
"sn": "Frogg",
"phone": "01233xxxxx",
"hours": "80",
"rate": "90",
"amount": "800",
"vat": "100",
"agency": "test",
"start": "08/06/2017",
"end": "10/06/2017"
}]]
我似乎无法使自己诉诸于阵列。
最佳答案
您可以在哈希表上对相同的电子邮件地址及其项目使用闭包。
var data = [{ email: "alex@test.com", fn: "Alex", sn: "McPherson", phone: "01233xxxxx", hours: "40", rate: "20", amount: "200", vat: "60", agency: "test", start: "08/06/2017", end: "10/06/2017" }, { email: "mike@test.com", fn: "Mike", sn: "Mann", phone: "01233xxxxx", hours: "50", rate: "70", amount: "500", vat: "90", agency: "test", start: "08/06/2017", end: "10/06/2017" }, { email: "fred@test.com", fn: "Fred", sn: "Frogg", phone: "01233xxxxx", hours: "80", rate: "90", amount: "800", vat: "100", agency: "test", start: "08/06/2017", end: "10/06/2017" }, { email: "alex@test.com", fn: "Alex", sn: "McPherson", phone: "01233xxxxx", hours: "90", rate: "30", amount: "900", vat: "120", agency: "test", start: "08/06/2017", end: "10/06/2017" }],
result = data.reduce(function (hash) {
return function (r, o) {
if (!hash[o.email]) {
hash[o.email] = [];
r.push(hash[o.email]);
}
hash[o.email].push(o)
return r;
};
}(Object.create(null)), []);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }关于javascript - 根据值将javascript对象数组分组为自己的子对象数组，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/44433833/