我正在尝试将值与我的数组进行比较,但是,它无法正常工作。当值为安大略时,应将其返回缩写为“ ON”,而在数组列表中未找到该值时,应返回与输入时相同的值。第一个警报框返回“安大略省”?我在这里做错了什么:

function shorten(value) {

    var prov_states = [
        ['alberta','AB'],
        ['british Columbia','BC'],
        ['manitova','MB'],
        ['new brunswick','NB'],
        ['newfoundland and labrador','NL'],
        ['nova scotia','NS'],
        ['northwest territories','NT'],
        ['new brunswick','NB'],
        ['nunavut','NU'],
        ['ontario','ON'],
        ['prince edward island','PE'],
        ['quebec','QC'],
        ['saskatchewan','SK'],
        ['yukon','YT'],
        ['alabama','AL'],
        ['alaska','AK'],
        ['arizona','AZ'],
        ['arkansas','AR'],
        ['california','CA'],
        ['colorado','CO'],
        ['connecticut','CT'],
        ['delaware','DE'],
        ['florida','FL'],
        ['georgia','GA'],
        ['hawaii','HI'],
        ['idaho','ID'],
        ['illinois','IL'],
        ['indiana','IN'],
        ['iowa','IA'],
        ['kansas','KS'],
        ['kentucky','KY'],
        ['louisiana','LA'],
        ['maine','ME'],
        ['maryland','MD'],
        ['massachusetts','MA'],
        ['michigan','MI'],
        ['minnesota','MN'],
        ['mississippi','MS'],
        ['missouri','MO'],
        ['montana','MT'],
        ['nebraska','NE'],
        ['nevada','NV'],
        ['new hampshire','NH'],
        ['new jersey','NJ'],
        ['new mexico','NM'],
        ['new york','NY'],
        ['north carolina','NC'],
        ['north dakota','ND'],
        ['ohio','OH'],
        ['oklahoma','OK'],
        ['oregon','OR'],
        ['pennsylvania','PA'],
        ['rhode island','RI'],
        ['south carolina','SC'],
        ['south dakota','SD'],
        ['tennessee','TN'],
        ['texas','TX'],
        ['utah','UT'],
        ['vermont','VT'],
        ['virginia','VA'],
        ['washington','WA'],
        ['west virginia','WV'],
        ['wisconsin','WI'],
        ['wyoming','WY']
        ]


  for (var i=0, iLen=prov_states.length; i<iLen; i++) {

    if (value.toLowerCase() == prov_states[i][0]) { return prov_states[i][1]; }

    else { return value }

  }
}


function test() {

alert(shorten('Ontario'))

alert(shorten('DC'))


}

最佳答案

您可能想使用一个映射/关联数组,而不是现在的数组。这样做起来容易得多。

var prov_states = {
    "alberta": "AB",
    "british columbia": "BC",
    ...
}


然后,您可以执行以下操作:

return prov_states[value.toLowerCase()];


您的特定问题是由于找不到值时正在执行的操作:

else { return value }


这意味着,如果第一个匹配失败,则立即返回value。相反,只有在完全找不到匹配项时才应该这样做。

while循环应该工作:

var i = 0;
var state = null;
while(state === null && i < prov_states.length) {
    if(value.toLowerCase() === prov_states[i][0]) {
        state = prov_states[i][1];
    }

    i++;
}

return state === null ? value : state; //or just return state if you are okay with null


我看到的另一个问题是,您将BC称为"british Columbia",这将永远不会匹配,因为您正在调用value.toLowerCase(),这会小写整个字符串。

关于javascript - 将值与数组进行比较,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/31414016/

10-09 15:31
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