c++ - 遇到数组问题:/

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到目前为止，这是我的代码

int main()
{
    srand(time(0));
    int inputnum,occurrences;
    occurrences = 0;
    cout<<"Enter a number to check the occurences"<<endl;
    cin>>inputnum;
    int arrayofnum[10] = {(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201),(rand()%201)} ;
    cout<<arrayofnum[0]<<","<<arrayofnum[1]<<","<<arrayofnum[2]<<","<<arrayofnum[3]<<","<<arrayofnum[4]<<","<<arrayofnum[5]<<","<<arrayofnum[6]<<","<<arrayofnum[7]<<","<<arrayofnum[8]<<","<<arrayofnum[9]<<endl;
    for(int i=1;i<=10;i++)
    {
        if(inputnum == arrayofnum[i])
            occurrences++;
    }

    cout<<"The number of occurrences of "<<inputnum<<"in the random list is "<<occurrences<<" times"<<endl;

    system("pause");
    return 0;
}

我的目标是检查输入的数字在数组中显示了多少次
但是，if语句似乎给我带来麻烦，任何人都可以帮忙吗？

最佳答案

看起来您正在访问数组末尾的内容：

if (inputnum == arrayofnum[i])

您的for循环允许i在终止之前取值10，因此在最后一次迭代中，您将访问arrayofnum[10]。数组中的最后一个元素是arrayofnum[9]。

请记住，c ++中的数组是从零开始的，因此您只需要像这样调整for循环即可：

for (int i = 0; i < 10; i++) {
   /* stuff */
}