当我调用GET api / home API端点时,我得到了某种数据结构-有两个数组:一个数组用于Books,一个数组用于Magazines。我想在每行四个项目的网格中显示项目,但是我不确定该怎么做。我还需要保持这些项目(淘汰)可见-在我的viewModel中,我有:

var mapping = {
        create: function(options) {
            //customize at the root level.
            var innerModel = ko.mapping.fromJS(options.data);

            return innerModel;
        }
    };

    var homeViewModel = ko.mapping.fromJS(homeData, mapping);
    //debugger;
    return homeViewModel;


在我看来,我有:

<div class="row-fluid">
        <!-- ko foreach: books -->
        <div class="span3">
        </div>
        <!-- /ko -->

        <!-- ko foreach: magazines -->
        <div class="span3">
        </div>
        <!-- /ko -->
</div>


但是我需要为每行包含一个“行流体”,其中包含四项,除非它是最后一行,它可以包含少于四项(书或杂志)。现在,它只是包含所有内容的单个“行流体”,因此布局已全部废弃。

我在想我可以使用元素的$ id来确定是否应该创建新的行流体($ id%4 == 0),但是我不确定如何做到这一点,或如何重组ViewModel。任何提示将不胜感激!

homeData定义如下:

 var homeData = {
        "$id": "1",
        "totalBooks": 40,
        "totalMagazines": 20,
        "books": [
            {
                "$id": "2",
                "bookId": 1,
                "title": "Test Title"
            },
            {
                "$id": "3",
                "bookId": 2,
                "title": "Test Title"
            },
            {
                "$id": "4",
                "bookId": 3,
                "title": "Test Title"
            },
            {
                "$id": "5",
                "bookId": 4,
                "title": "Test Title"
            },
            {
                "$id": "6",
                "bookId": 5,
                "title": "Test Title"
            },
            {
                "$id": "7",
                "bookId": 6,
                "title": "Test Title"
            },
            {
                "$id": "8",
                "bookId": 7,
                "title": "Test Title"
            },
            {
                "$id": "9",
                "bookId": 8,
                "title": "Test Title"
            }
        ],
        "magazines": [
            {
                "$id": "9",
                "magazineId": 1,
                "title": "test magazine 0",
            },
            {
                "$id": "10",
                "magazineId": 2,
                "title": "test magazine 0",
            },
            {
                "$id": "11",
                "magazineId": 3,
                "title": "test magazine 0",
            },
            {
                "$id": "12",
                "magazineId": 4,
                "title": "test magazine 0",
            },
            {
                "$id": "13",
                "magazineId": 5,
                "title": "test magazine 0",
            }]};

最佳答案

我为此用例所做的是使计算的可观察值成为数组数组,第一级为行,第二级为列。

var groupObsArray = function(itemsPerGroup,observableArray) {
    return ko.computed(function() {
        var obsArrData = observableArray();
        var groupedItems = [];
        var aGroup = [];
        for (var i=0;i<obsArrData.length;i++)
        {
            aGroup.push(obsArrData[i])
            if(i%itemsPerGroup === 0) {
                groupedItems.push(aGroup);
                aGroup = [];
            }
        }
        return groupedItems;
    });
}
var mapping = {
    create: function(options) {
        //customize at the root level.
        var innerModel = ko.mapping.fromJS(options.data);

        return innerModel;
    }
};

var homeViewModel = ko.mapping.fromJS(homeData, mapping);

homeViewModel.MagazineRows = groupObsArray(4,homeViewModel.magazines);
homeViewModel.BookRows = groupObsArray(4,homeViewModel.books);


标记

<div class="readingMaterials magazines" data-bind="foreach:MagazineRows">
    <div class="row-fluid" data-bind="foreach:$data">
        <div class="span3" data-bind="text:title">
        </div>
    </div>
</div>

10-04 15:46
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