我有一些奇怪的性能结果,我无法完全解释。
看来这条线

d = new double[4, 4]{{1, 0, 0, 0},
                     {0, 1, 0, 0},
                     {0, 0, 1, 0},
                     {0, 0, 0, 1},};

比这慢四倍
d = new double[4, 4];
d[0, 0] = 1; d[0, 1] = 0; d[0, 2] = 0; d[0, 3] = 0;
d[1, 0] = 0; d[1, 1] = 1; d[1, 2] = 0; d[1, 3] = 0;
d[2, 0] = 0; d[2, 1] = 0; d[2, 2] = 1; d[2, 3] = 0;
d[3, 0] = 0; d[3, 1] = 0; d[3, 2] = 0; d[3, 3] = 1;

(并且甚至没有考虑在这个示例中我可以忽略所有这些= 0分配的事实)

我知道由于边界检查,在C#中循环遍历多维数组会很慢。但是这里没有循环,不需要边界检查,并且整个数组初始化程序行都可以在编译时解析。

但是,第二个代码块必须首先将数组初始化为零,然后分别覆盖每个值。
那么这是什么问题呢?

如果性能存在问题,初始化此数组的最佳方法是什么?

我使用以下代码来衡量性能:
using System;
using System.Diagnostics;
class Program
{
    public static double[,] d; // global static variable to prevent the JIT optimizing it away

    static void Main(string[] args)
    {
        Stopwatch watch;
        int numIter = 10000000; // repeat all tests this often

        double[,] d2 = new double[4, 4]{{1, 0, 0, 0},
                                        {0, 1, 0, 0},
                                        {0, 0, 1, 0},
                                        {0, 0, 0, 1},};

        // ================================================================
        // use arrayInitializer: slowest
        watch = Stopwatch.StartNew();
        for (int i = 0; i < numIter; i++)
        {
            d = new double[4, 4]{{1, 0, 0, 0},
                                {0, 1, 0, 0},
                                {0, 0, 1, 0},
                                {0, 0, 0, 1},};
        }
        Console.WriteLine("ArrayInitializer: \t{0:0.##########}ms", watch.ElapsedMilliseconds * 1.0 / numIter);

        // ================================================================
        // use Array.Copy: faster
        watch = Stopwatch.StartNew();
        for (int i = 0; i < numIter; i++)
        {
            d = new double[4, 4];
            Array.Copy(d2, d, d2.Length);
        }
        Console.WriteLine("new + Array.Copy: \t{0:0.##########}ms", watch.ElapsedMilliseconds * 1.0 / numIter);

        // ================================================================
        // direct assignment: fastest
        watch = Stopwatch.StartNew();
        for (int i = 0; i < numIter; i++)
        {
            d = new double[4, 4];
            d[0, 0] = 1; d[0, 1] = 0; d[0, 2] = 0; d[0, 3] = 0;
            d[1, 0] = 0; d[1, 1] = 1; d[1, 2] = 0; d[1, 3] = 0;
            d[2, 0] = 0; d[2, 1] = 0; d[2, 2] = 1; d[2, 3] = 0;
            d[3, 0] = 0; d[3, 1] = 0; d[3, 2] = 0; d[3, 3] = 1;
        }
        Console.WriteLine("direct assignment: \t{0:0.##########}ms", watch.ElapsedMilliseconds * 1.0 / numIter);
    }
}

结果:
ArrayInitializer:       0,0007917ms
new + Array.Copy:       0,0002739ms
direct assignment:      0,0002281ms

最佳答案

这是数组初始化程序的很好解释,以及为什么会看到这样不同的结果:http://bartdesmet.net/blogs/bart/archive/2008/08/21/how-c-array-initializers-work.aspx

基本上-数组初始化程序涉及创建自定义结构,而直接分配每个项目只是在堆栈中直接分配,尽管速度更快。

10-02 04:07
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