javascript - 如何在JavaScript中将数组1 [对象数组]与数组2进行比较

我想将数组1与数组2进行比较，数组1具有对象数组。数组2中可用的任何项目也应该在数组1上可用。如果是这样，那么我必须将项目从数组2推到新数组，然后，我返回新创建的finalArray。
我做了代码，正如我提到的那样，它工作正常，但是，下面的代码执行了“ for循环”许多我不需要的项目。

我想避免很多循环执行。

var arr1 = [{"count":1,"name":"hitler"},{"count":1,"name":"cool"},{"count":1,"name":"cooola"},{"count":1,"name":"cute"},{"count":1,"name":"nyle"},{"count":1,"name":""},{"count":1,"name":"path"},{"count":1,"name":"root"},{"count":1,"name":"sssstag"},{"count":1,"name":"ssssu tag"},{"count":1,"name":"sutag"},{"count":1,"name":"tag2"},{"count":1,"name":"arrogant"},{"count":1,"name":"test01"},{"count":1,"name":"test10"},{"count":1,"name":"uber"},{"count":1,"name":"union"},{"count":1,"name":"assettag"},{"count":1,"name":"wire"}];

function intersect_arrays(a, b) {

    var matches = [];

    for ( var i = 0; i < a.length; i++ ) {
        for ( var e = 0; e < b.length; e++ ) {
            if ( a[i].name === b[e] ) matches.push( b[e] );
        }
    }
    return matches;
}


var arr2 = ["hilter","arrogant","cool","uber"];

var finalArray = intersect_arrays(arr1, arr2);
console.log(finalArray);

有人帮助我以更好的方式实现这一目标吗？

最佳答案

将内部for循环替换为

var matches = a.filter( function(item){ return b.indexOf( item.name ) > -1 } );

例如

var arr1 = [{
  "count": 1,
  "name": "hitler"
}, {
  "count": 1,
  "name": "cool"
}, {
  "count": 1,
  "name": "cooola"
}, {
  "count": 1,
  "name": "cute"
}, {
  "count": 1,
  "name": "nyle"
}, {
  "count": 1,
  "name": ""
}, {
  "count": 1,
  "name": "path"
}, {
  "count": 1,
  "name": "root"
}, {
  "count": 1,
  "name": "sssstag"
}, {
  "count": 1,
  "name": "ssssu tag"
}, {
  "count": 1,
  "name": "sutag"
}, {
  "count": 1,
  "name": "tag2"
}, {
  "count": 1,
  "name": "arrogant"
}, {
  "count": 1,
  "name": "test01"
}, {
  "count": 1,
  "name": "test10"
}, {
  "count": 1,
  "name": "uber"
}, {
  "count": 1,
  "name": "union"
}, {
  "count": 1,
  "name": "assettag"
}, {
  "count": 1,
  "name": "wire"
}];

var arr2 = ["hilter", "arrogant", "cool", "uber"];

function intersect_arrays(a, b) {
  var matches = a.filter(function(item) {
    return b.indexOf(item.name) > -1
  });
  matches = matches.map( function(item){ return item.name } );
  return matches;
}

console.log(intersect_arrays(arr1, arr2))