我有一个看起来像这样的变体数组:

“狗”
“猫”
“马”

我想用覆盖这些值

1.01
2.02
3.03


码:

sumHolder = loanSums(x)
If sumHolder = "N/A" Then
    sumHolder = "0"
End If
loanSums(x) = vbNull
loanSums(x) = sumHolder + trimmedRange(i, trimmedRngCols.paymentAmt)


我试图只在字符串上分配双精度字,但出现类型不匹配的情况。关于如何执行此操作的任何想法

最佳答案

你做的不对。

一维变量数组:

Dim a As Long, vals As Variant

vals = Array("dog", "cat", "horse")

For a = LBound(vals) To UBound(vals)
    Debug.Print vals(a)
    vals(a) = CDbl(a + 1 + (a + 1) / 100)
Next a

For a = LBound(vals) To UBound(vals)
    Debug.Print vals(a)
Next a


立即窗口中的结果:

dog
cat
horse
 1.01
 2.02
 3.03


二维变量数组:

dim a as long, vals as variant, tmp as variant

vals = range("A2:E4").value2

debug.print lbound(vals, 1) & ":" & ubound(vals, 1)  '1:3, 3 'rows' in array
debug.print lbound(vals, 2) & ":" & ubound(vals, 2)  '1:5, 5 'columns' in array

for a = lbound(vals, 1) to ubound(vals, 1)
    debug.print vals(a, 1) & " - " & vals(a, 3)
    tmp = vals(a, 1)
    vals(a, 1) = vals(a, 3)
    vals(a, 3) = tmp
next a

for a = lbound(vals, 1) to ubound(vals, 1)
    debug.print vals(a, 1) & " - " & vals(a, 3)
next a

range("A2").resize(ubound(vals, 1), ubound(vals, 2)) = vals


立即窗口和工作表中的结果:

1:3
1:5
dog - 1.01
cat - 2.02
horse - 3.03
1.01 - dog
2.02 - cat
3.03 - horse


在处理之前arrays - 第一个索引中带有字符串的变体数组-用双类型不匹配覆盖它-LMLPHP在处理后arrays - 第一个索引中带有字符串的变体数组-用双类型不匹配覆盖它-LMLPHP进行以下操作: 进行处理之前

我提供了一些前后图像,以便您可以通过单元格值的左对齐(文本)和右对齐(数字)清楚地看到不应该将变体编号交换为文本,反之亦然一个问题。您的“类型不匹配”必须不是价值转移。

07-24 19:25
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