c - 通过多个函数传递变量，未获得理想的结果

在我把它分解成函数之前，我已经让它工作了。我肯定这只是一个&或者*我错过了某个地方，但我似乎想不出来用户输入一个数字，然后在菜单上选择F，让它打印0号我正在display（）函数中获取垃圾。

#include <stdio.h>

char menu();
int read_int(int number);
void display(int number);

int main(int argc, char ** argv) {
int number = 0;
char choice = 'O';
while (choice != 'X'){


    choice = menu();

    if (choice != 'N' && choice != 'F' && choice != 'X'){
        printf("Invalid Input. Enter N, F, or X\n");
    }

    else if (choice == 'N'){
        number = read_int(number);

    }

    else if (choice == 'F'){
        display(number);
    }




}

}


char menu ()
{
char i;
printf("\nEnter N to enter an integer from 0 to 20\nEnter F to display the first N+1 numbers (beginning with zero) on the console \nEnter X to quit the program \n");

printf("Your Choice: ");
scanf("%s",  &i);
return i;
}

int read_int(number)
{
//int number = 0;
printf("\nEnter an integer 0-20: ");
scanf("%d", &number);
if (number >=0 && number <=20)
    return number;
else{
    printf("Enter a valid number between 0 and 20");
    read_int(number);
}
}

void display(answer)
{
int count = 0;
printf("\nNumber equals: ");
printf("%d", answer);
//while (count <= number){
//  printf("%d",count);
//  printf(" , ");
//  count++;
//}
}

它似乎正在使用此代码：

#include <stdio.h>

char menu();
int read_int(int number);
void display(int answer);

int main(int argc, char ** argv) {
    int number = 0;
    char choice = 'O';
    while (choice != 'X'){


    choice = menu();

    if (choice != 'N' && choice != 'F' && choice != 'X'){
        printf("Invalid Input. Enter N, F, or X\n");
    }

    else if (choice == 'N'){
        number = read_int(number);
        printf("\nNumber equals: ");
        printf("%d", number);

    }

    else if (choice == 'F'){
        //printf("\nNumber equals: ");
        //printf("%d", number);
        display(number);
    }




}

}


char menu ()
{
    char i;
    printf("\nEnter N to enter an integer from 0 to 20\nEnter F to display the first N+1 numbers (beginning with zero) on the console \nEnter X to quit the program \n");

    printf("Your Choice: ");
    scanf("%s",  &i);
    return i;
}

int read_int(int number)
{
number = 0;
    printf("\nEnter an integer 0-20: ");
    scanf("%d", &number);
    if (number >=0 && number <=20)
        return number;
    else{
        printf("Enter a valid number between 0 and 20");
        return read_int(number);
    }
}

void display(int answer)
{
int count = 0;
//printf("\nNumber equals: ");
//printf("%d", answer);
//int toprint = answer;
while (count <= answer){
    printf("%d",count);
    printf(" , ");
    count=count+1;
}
}

现在把它转换成程序集哦，孩子！

最佳答案

char menu (void){
    char i[2];
    printf("\nEnter N to enter an integer from 0 to 20\nEnter F to display the first N+1 numbers (beginning with zero) on the console \nEnter X to quit the program \n");
    printf("Your Choice: ");
    scanf("%1s", i);
    return *i;
}

int read_int(int number)//add int
{
    printf("\nEnter an integer 0-20: ");
    scanf("%d", &number);
    if (number >=0 && number <=20)
        return number;
    else{
        printf("Enter a valid number between 0 and 20");
        return read_int(number);//add return
    }
}

void display(int answer)//add int
{
    int count = 0;
    printf("\nNumber equals: ");
    printf("%d\n", answer);
}

关于c - 通过多个函数传递变量，未获得理想的结果，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/31248374/