尝试编写一个方便的toString()
方法,列出一个对象的所有属性及其赋值。
class FooModel
{
func toString() -> String
{
var result = "[\(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
result += "\(child.label): \(child.value), "
}
return "\(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String?
var showAnnouncement = false
var isCompleted = false
var completedOn:String?
var suiteMode = 0
var url = ""
}
输出:
[FooProject Optional("id"): 0, Optional("name"): , Optional("announcement"): nil, Optional("showAnnouncement"): false, Optional("isCompleted"): false, Optional("completedOn"): nil, Optional("suiteMode"): 0, Optional("url"): , ]
首先,它不列出实际值,而是列出默认值。为什么?
第二,有没有一种方法可以去掉
Optional
封装? 最佳答案
根据关于Child
here的文档:
孩子
反射实例结构的元素。可在适当时使用可选标签,例如表示
存储属性或活动枚举事例的,并将用于查找
当字符串传递给子代方法时。
因为镜像中的子类型定义为
typealias Child = (label: String?, value: Any)
因此,所有名称都打印为选项。
要获取标签名称,可以使用可选绑定
我做了一些改变,并在操场上尝试过:
class FooModel
{
func toString() -> String
{
var result = "[\(String(describing: type(of: self))) "
let mirror = Mirror(reflecting: self)
mirror.children.forEach
{
child in
print(child)
if let label = child.label {
result += "\(label): \(child.value), "
}
}
return "\(result)]"
}
}
class FooProject : FooModel
{
var id = 0
var name = ""
var announcement:String!
var showAnnouncement = false
var isCompleted = false
var completedOn:String!
var suiteMode = 0
var url = ""
init(id: Int, name: String, completedOn: String) {
self.completedOn = completedOn
self.id = id
self.name = name
//...
}
}
let fooProj = FooProject(id: 10, name: "Name", completedOn: "Sunday")
print(fooProj.toString())
输出为:
[FooProject id: 10, name: Name, announcement: nil, showAnnouncement: false, isCompleted: false, completedOn: Sunday, suiteMode: 0, url: , ]
嗯…
关于swift - Swift 3反射 - 迭代属性,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/46107334/