我有这个字符串:

var str = '<p>paragraph<a>link</a></p>
           <div class="myclass">
               <div>something</div>
               <div style="mystyle">something</div>
               <b><a href="#">link</a></b>
               <b><a href="#" name="a name">link</a></b>
               <b style="color:red">bold</b>
               <img src="../path" alt="something" />
               <img src="../path" alt="something" class="myclass" />
           </div>';


我想删除除hrefsrcalt之外的所有属性。所以这是预期的结果:

/*
<p>paragraph<a>link</a></p>
<div>
    <div>something</div>
    <div>something</div>
    <b><a href="#">link</a></b>
    <b><a href="#">link</a></b>
    <b>bold</b>
    <img src="../path" alt="something">
    <img src="../path" alt="something">
</div>


我怎样才能做到这一点?



我可以选择没有用的它们:

/<[a-z]+ .*?(href|src|alt)="[^"]+"/g

最佳答案

var str = `<p>paragraph<a>link</a></p>
           <div class="myclass">
               <div>something</div>
               <div style="mystyle">something</div>
               <b><a href="#">link</a></b>
               <b><a href="#" name="a name">link</a></b>
               <b style="color:red">bold</b>
               <img src="../path" alt="something" />
               <img src="../path" alt="something" class="myclass" />
           </div>`;
var div = document.createElement("div");
div.innerHTML=str;
div.querySelectorAll("*").forEach(function(el){
  for (var i = 0, atts = el.attributes, n = atts.length; i < n; i++){
    var att = atts[i].nodeName;
    if (["src","alt","href"].indexOf(att) ==-1) el.removeAttribute(att);
  }
});
// console.log(div); alert shows it more clearly
alert(div.innerHTML);





PS:请注意,您需要反引号来引用带有嵌入式换行符的字符串

07-24 09:50
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