php - PHP Script正在连接到数据库，但即使已连接也不会返回表值。

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          <main class="mdl-layout__content">
            <div class="page-content">
                <!-- Your content goes here -->
                <?php
                    include("dbforforum.php");
                    $subForum = "";
                    $results = $mysqli->query("SELECT * FROM `SubForumList`");
                    echo $results;
                    for ($i = 0; $i < $results->num_rows; $i++)
                    {
                        $results->data_seek($i);
                        $row = $results->fetch_assoc();
                        $subForum = $row['Name'];
                        echo $subForum;
                        echo $subForum;
                    }
                ?>
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每当此循环通过时，我都试图在PHP中的SQL表$row['subForum']的'subForum'行中回显HTML，但是由于某种原因，它没有连接。

即使在我的数据库配置文件dbforforum.php中，它也显示已成功连接：

<?php

$mysqli = new mysqli("localhost", "root", "", "Forum");
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";

?>

我对此感到非常困惑。任何帮助表示赞赏。

注意：我最近从Windows切换到Mac（不是我的选择），因此从WAMP转到MAMP。不知道这是否与任何事情有关。

最佳答案

应该是这个

在您的数据库配置中

$mysqli = new mysqli("localhost", "root", "", "Forum"); //the variable here is mysqli
 if ($conn->connect_error) { //the error here is $conn because it isn't the variable above so change the variable to $mysqli
  die("Connection failed: " . $conn->connect_error); //and here too to $mysqli
 }
 echo "Connected successfully";

变化：

$mysqli = new mysqli('localhost', 'root', '', 'databasename'); //connect db

if($mysqli->connect_errno){
  die("Error! ".$mysqli->connect_errno);
}

if($result = $mysqli->query("SELECT * FROM SubForumlist")){
  echo $result->num_rows //num_rows == your data you want to echo
}

关于php - PHP Script正在连接到数据库，但即使已连接也不会返回表值。，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32001766/