这是我的array.php,其中json数据来自数据库,而我正在从下面的脚本中获得完美的输出

$table = [];
  $table['cols'] = array(
      array('id' => '', 'label' => 'Topping', 'type' => 'string'),
      array('id' => '', 'label' => 'Slices', 'type' => 'number')
      );

$tableName = array('1' => "tb", '2' => 'tb1');
foreach ($tableName as $key => $value) {

    $row = [];
    $qry = "SELECT topping, slices FROM $value";
    $result = mysqli_query($con,$qry);
     foreach ($result as $row) {
        $temp = [];
          $temp[] = array('v' => (string) $row['topping']);
      $temp[] = array('v' => (int) $row['slices']);
      $rows[] = array('c' => $temp);
     }
     $result->free();
             $table['rows'] = $rows;
}
mysqli_close($con);
$jsonTable = json_encode($table, true);
echo $jsonTable;




** Array.php数据输出示例:**

{"cols":[{"id":"","label":"Topping","type":"string"},{"id":"","label":"Slices","type":"number"}],"rows":[{"c":[{"v":"MAX"},{"v":150}]},{"c":[{"v":"MAX1"},{"v":59}]},{"c":[{"v":"MAX2"},{"v":15}]},{"c":[{"v":"MAX3"},{"v":153}]},{"c":[{"v":"MAX4"},{"v":8}]},{"c":[{"v":"MAX5"},{"v":25}]},{"c":[{"v":"MAX6"},{"v":65}]}]


}



这是我的Ajax函数,其中我从array.php校准数据

var jsonData = $.ajax({
url: "array.php",
dataType:"json",
}).responseText;


var data = new google.visualization.DataTable(JSON.parse(jsonData));
 var options = {
        标题:“我的日常活动”
        };
var chart = new google.visualization.PieChart(document.getElementById('piechart'));
chart.draw(数据,选项);

**但是我仍然对此有误,请帮忙**

最佳答案

好的,我已经将您的json输出复制到一个php文件(jsondata.php)中,如下所示:

$out = '{"cols":[{"id":"","label":"Topping","type":"string"},{"id":"","label":"Slices","type":"number"}],"rows":[{"c":[{"v":"MAX"},{"v":150}]},{"c":[{"v":"MAX1"},{"v":59}]},{"c":[{"v":"MAX2"},{"v":15}]},{"c":[{"v":"MAX3"},{"v":153}]},{"c":[{"v":"MAX4"},{"v":8}]},{"c":[{"v":"MAX5"},{"v":25}]},{"c":[{"v":"MAX6"},{"v":65}]}]}';
echo $out;


使用它,我对您的JavaScript进行了一些修改

  var jsonData = $.ajax({
      url: "jsondata.php",
      dataType: "json",
      async: false
      }).responseText;

  // Create our data table out of JSON data loaded from server.
  var data = new google.visualization.DataTable(jsonData);

  // Instantiate and draw our chart, passing in some options.
  var chart = new google.visualization.PieChart(document.getElementById('piechart'));
  var options = { title: 'My Daily Activities' };
  chart.draw(data, options);


注意两件事:


Ajax调用中的async:false。这实际上违反了Ajax的本质,但这是google显示示例的方式,这也是解决问题的最简单方法。
var data = new google.visualization.DataTable(jsonData);


这对我有用,希望它能解决您的问题。

关于javascript - 谷歌图表不显示与PHP中的ajax调用,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/35460108/

10-10 19:08
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