我有一组三个组合框(下拉列表),这些组合框由PHP用数据库中的值填充。我已经通过将回显的Submit按钮更改为type='submit'并加载php页面本身来测试了这些组合框。他们以这种方式毫不费力地工作。

但是,当我加载Ajax页面时,提交按钮拒绝触发Ajax函数。我通过使用html创建一组静态组合框来测试该页面,在这种情况下,Ajax可以顺利启动。但是使用PHP创建的组合框不会触发Ajax。

我希望有人可以阐明我的代码存在的问题。

HTML和jQuery:

<div id="gallery_container">
    <ul class="new_arrivals_gallery"></ul>
    <div class="pagination"></div>
</div>
<script type="text/javascript" src="js/libs/jquery-1.6.1.min.js"></script>
<script>

$(document).ready(function() {

    function loadData(imgFamily, imgClass, imgGender){
        $.ajax
        ({
            type: "GET",
            url: "filter_test.php",
            data: {imgFamily:imgFamily, imgClass:imgClass, imgGender:imgGender},
            success: function(data) {
                $("#gallery_container").html(data);
            },
        });
    }
    loadData(1);  // For first time page load default results

    //Bind keypress event to Ajax call
    $('.filter').keypress(function(e) {
        if(e.keyCode == 13) {
            var imgFamily = $('#imgFamily').attr('value');
            var imgClass = $('#imgClass').attr('value');
            var imgGender = $('#imgGender').attr('value');
            //Fetch the images
            loadData(imgFamily, imgClass, imgGender);
        }
    });

    //Bind the click event to Ajax call on submit
    $("#submit").click(function(){
        var imgFamily = $('#imgFamily').attr('value');
        var imgClass = $('#imgClass').attr('value');
        var imgGender = $('#imgGender').attr('value');
        //Fetch the images
        loadData(imgFamily, imgClass, imgGender);
    })
});


PHP(尽管我不认为问题出在这里):

我只显示一个组合框以节省空间,因为它们都是一样的

// Queries for combo boxes
$imgFamily_query = "SELECT DISTINCT imgFamily FROM images WHERE $clause";
$imgClass_query = "SELECT DISTINCT imgClass FROM images WHERE $clause";
$imgGender_query = "SELECT DISTINCT imgGender FROM images WHERE $clause";


// Create the form and combo boxes
echo "<form name='refine' action=''>
        <fieldset><legend>Refine Results</legend>";

    // imgFamily combo box
    if($imgFamily_result = mysql_query($imgFamily_query))  {
      if($imgFamily_success = mysql_num_rows($imgFamily_result) > 0) {
        // Start combo-box
        echo "<label for='imgFamily' id='imgFamily_label'>Choose a family</label>\n
            <select class='filter' id='imgFamily' name='imgFamily'>\n
            <option value='1'></option>\n";
        // For each item in the results...
        while ($imgFamily_row = mysql_fetch_array($imgFamily_result))
          // Add a new option to the combo-box
          echo "<option value='$imgFamily_row[imgFamily]'>$imgFamily_row[imgFamily]</option>\n";
        // End the combo-box
        echo "</select>\n";
      } else { echo "No results found."; }
    } else { echo "Failed to connect to database."; }


    // Add a submit button to the form
    echo "</fieldset>
        <fieldset><input type='button' name='submit' value='submit' id='submit'></fieldset>
    </form>";


非常感谢您的帮助。

最佳答案

您插入表单,从而覆盖了提交事件所绑定的元素。插入新表单后,应重新执行绑定事件的代码。

较干净的方法是返回仅包含已修改信息的JSON对象或XML,并更新当前表单,而不是插入一个新表单,但这将需要更多工作。

function loadData(imgFamily, imgClass, imgGender){
    $.ajax
    ({
        type: "GET",
        url: "filter_test.php",
        data: {imgFamily:imgFamily, imgClass:imgClass, imgGender:imgGender},
        success: function(data) {
            $("#gallery_container").html(data);

            bindEvents(); // <---- Call it here
        },
    });
}

// Separate function
function bindEvents()
{
    //Bind keypress event to Ajax call
    $('.filter').keypress(function(e) {
        if(e.keyCode == 13) {
            var imgFamily = $('#imgFamily').attr('value');
            var imgClass = $('#imgClass').attr('value');
            var imgGender = $('#imgGender').attr('value');
            //Fetch the images
            loadData(imgFamily, imgClass, imgGender);
        }
    });

    //Bind the click event to Ajax call on submit
    $("#submit").click(function(){
        var imgFamily = $('#imgFamily').attr('value');
        var imgClass = $('#imgClass').attr('value');
        var imgGender = $('#imgGender').attr('value');
        //Fetch the images
        loadData(imgFamily, imgClass, imgGender);
    })
}

$(document).ready(function() {

    loadData(1);  // For first time page load default results

    bindEvents(); // <---- And here (where your code originally was).
});

07-28 05:14
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