我对php还不熟悉,所以我一直在尝试制作一个php页面,将信息添加到Mysql数据库中。但是当我在表单上按下submit时,它会指向php页面,而什么也不会发生。空白页。
这是我目前所拥有的。
形式

<table class="table" >
  <h2>Resturants</h2>
  <tbody>
    <form data-toggle="validator" enctype="multipart/form-data" action="editRestaurants.php" method="post">
      <tr>
        <td><label for="inputName" class="control-label" style="font-size:17px;">Title :</label></td>
        <td><input type="text" class="form-control" id="title" name="title" required></td>
      </tr>
      <tr>
        <td><label for="inputName" class="control-label" style="font-size:17px;">Text :</label></td>
        <td><textarea style="width:300px;height:100px" class="form-control" id="text" name="text" required></textarea><br/></td>
      </tr>
      <tr>
        <td><label for="inputName" class="control-label" style="font-size:17px;">Link :</label></td>
        <td><input type="text" class="form-control" id="link" name="link" required></td>
      </tr>
      <tr>
        <td><label for="inputName" class="control-label" style="font-size:17px;">Photo:</label></td>
        <td><input type="file" id="image" class="form-control" name="image" accept="image/jpeg" required></td>
      </tr>
      <tr>
        <td><input type="submit" value="Submit" style="font-size:17px;" id="submit"></td>
      </tr>
    </form>
  </tbody>
</table>

这是php文件
include('connection.php');
session_start();
$title=$_POST['title'];
$text=$_POST['text'];
$link=$_POST['link'];
$image=$_FILES['image'];
$imagename=$image['name'];
if(empty($imagename))
{
    $imagename="defualt.jpg";
}
if(!empty($title) && !empty($text))
{
    $query=mysqli_query($GLOBALS["___mysqli_ston"], 'INSERT INTO `resturant`(`ID`, `Title`, `ImagePath`, `Text`, `Link`, `Date`) VALUES (NULL,'$title','$imagename','$text','$link',CURRENT_DATE())');


    if(!empty($image))
    {
    $target_dir= "NewsImages/";
    $target_file = $target_dir . basename($imagename);
    move_uploaded_file($image["tmp_name"], $target_file);

    }

    $_SESSION['status']="Successful";
}
else
{
    $_SESSION['status']="Please check all fields";

}

header('Location:cms.php');

最佳答案

您的$query有语法错误。以下代码将起作用:

$query=mysqli_query($GLOBALS["___mysqli_ston"], "INSERT INTO `resturant`(`ID`, `Title`, `ImagePath`, `Text`, `Link`, `Date`) VALUES (NULL,'$title','$imagename','$text','$link',CURRENT_DATE())");

我简化了你的代码。现在,它将在重定向到cms.php之前检查文件是否已成功上载。
if(empty($imagename)) {
    $imagename="defualt.jpg";
}

if(!empty($title) && !empty($text)) {
    $query=mysqli_query($GLOBALS["___mysqli_ston"], "INSERT INTO `resturant`(`ID`, `Title`, `ImagePath`, `Text`, `Link`, `Date`) VALUES (NULL,'$title','$imagename','$text','$link',CURRENT_DATE())");

    $target_dir= "NewsImages/";
    $target_file = $target_dir . basename($imagename);

    if(move_uploaded_file($image["tmp_name"], $target_file)) {
        $_SESSION['status']="Successful";
        header('Location:cms.php');
        exit;
    } else {
        $_SESSION['status']="Something went wrong while uploading the image.";
    }

} else {
    $_SESSION['status']="Please check all fields";
}

07-24 09:37
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