我认为我对如何开发代码部分负责其余部分并检查是否可以从显示的更改类别中提取更改存在逻辑上的疑问。
它旨在评估您欠某人的零钱,并做出最有效的更改。

我当前的输出:

The change for 328.0 Euro cents is:
1.64   € 2
1.28   € 1
0.56   € 0.50
1.4   € 0.20
0.8   € 0.10
1.6   € 0.05
1.5   € 0.02
1.0   € 0.01


正确的输出:

The change for 328 Euro cents is:
1 €2
1 €1
0 €0.50
1 €0.20
0 €0.10
1 €0.05
1 €0.02
1 €0.01


我很沮丧,感谢您的帮助,谢谢。

import java.util.Scanner; // Enables user input

    public class Change {
       private static Scanner scnr;

    public static void main(String [] args) {
           scnr = new Scanner(System.in);
          double changeR      = 0; // User input
          double oneCent      = 0; // Number of one cent coins
          double twoCent      = 0; // Number of two cent coins
          double fiveCent     = 0; // Number of five cent coins
          double tenCent      = 0; // Number of ten cent coins
          double twentyCent   = 0; // Number of twenty cent coins
          double fiftyCent    = 0; // Number of fifty cent coins
          double oneEUC       = 0; // Number of one Euro cent coins
          double twoEUC       = 0; // Number of two Euro cent coins

          System.out.println("Please enter the amount of change in Euro cents to be returned (a number between 0 & 499): ");
          changeR = scnr.nextInt(); // Gathers user input

          System.out.println("The change for " + changeR + " Euro cents is: "); // Outputs users inputted value

          twoEUC = changeR / 200;
          changeR = changeR % 200;

          oneEUC = changeR / 100;
          changeR = changeR % 100;

          fiftyCent = changeR / 50;
          changeR = changeR % 50;

          twentyCent = changeR / 20;
          changeR = changeR % 20;

          tenCent = changeR / 10;
          changeR = changeR % 10;

          fiveCent = changeR / 5;
          changeR = changeR % 5;

          twoCent = changeR / 2;
          changeR = changeR % 2;

          oneCent = changeR / 1;
          changeR = changeR % 1;

          System.out.println( twoEUC + "   \u20ac" + " 2");
          System.out.println( oneEUC + "   \u20ac" + " 1");
          System.out.println( fiftyCent + "   \u20ac" + " 0.50");
          System.out.println( twentyCent + "   \u20ac" +" 0.20");
          System.out.println( tenCent + "   \u20ac" +" 0.10");
          System.out.println( fiveCent + "   \u20ac" +" 0.05");
          System.out.println( twoCent + "   \u20ac" +" 0.02");
          System.out.println( oneCent + "   \u20ac" +" 0.01");

          return;
       }
    }

最佳答案

与处理货币¹一样,您只需要处理整数。

将所有变量更改为int将为您提供正确的值,因为整数除法将确保该238 / 200 = 1。而不是双除会导致238.0 / 200.0 = 1.19

¹用代码(以及现实生活)处理金钱是一个难题。您需要以用户可读的形式显示输出,因此由于双重不精确的问题,您不想将价格显示为5.0001 €,但是您不想让计算进行“急切”的舍入,因此最终结果已关闭。最简单的方法之一是采用最小的“原子”,即美分并仅进行处理。

Why not use double or float to represent currency

10-02 03:31
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