我继续在此JavaScript代码段中添加更多if statements
以显示和隐藏图像缩略图。如果src
为空,则该片段仅隐藏缩略图。
我需要一种将代码段转换为数组和循环的方法,这样,当我在if statements
中添加更多图像时,就不必继续添加更多的div
。
我将如何以某种方式压缩我的代码,以免最终没有成百上千的if statements
?
我必须使用JavaScript。 jQuery不是一个选择。
<div id="thumbs">
<a href="#img1"><img id="thumb1" src="photo.png"></a>
<a href="#img2"><img id="thumb2" src=""></a>
<a href="#img3"><img id="thumb3" src=""></a>
<a href="#img4"><img id="thumb4" src=""></a>
<a href="#img5"><img id="thumb5" src=""></a>
<a href="#img6"><img id="thumb6" src=""></a>
<a href="#img7"><img id="thumb7" src="picture.jpg"></a>
<a href="#img8"><img id="thumb8" src=""></a>
<a href="#img9"><img id="thumb9" src=""></a>
<a href="#img10"><img id="thumb10" src=""></a>
<a href="#img11"><img id="thumb11" src="stock.gif"></a>
<a href="#img12"><img id="thumb12" src=""></a>
</div>
<script>
function checkThumbs() {
var thumb1 = document.getElementById("thumb1"); var img1 = document.getElementById("img1");
var thumb2 = document.getElementById("thumb2"); var img2 = document.getElementById("img2");
var thumb3 = document.getElementById("thumb3"); var img3 = document.getElementById("img3");
var thumb4 = document.getElementById("thumb4"); var img4 = document.getElementById("img4");
var thumb5 = document.getElementById("thumb5"); var img5 = document.getElementById("img5");
var thumb6 = document.getElementById("thumb6"); var img6 = document.getElementById("img6");
var thumb7 = document.getElementById("thumb7"); var img7 = document.getElementById("img7");
var thumb8 = document.getElementById("thumb8"); var img8 = document.getElementById("img8");
var thumb9 = document.getElementById("thumb9"); var img9 = document.getElementById("img9");
var thumb10 = document.getElementById("thumb10"); var img10 = document.getElementById("img10");
var thumb11 = document.getElementById("thumb11"); var img11 = document.getElementById("img11");
var thumb12 = document.getElementById("thumb12"); var img12 = document.getElementById("img12");
if ((thumb1).getAttribute("src") == "") {
thumb1.style.display = "none";
img1.style.display = "none";
thumb1.src = "clearpixeldot.png";
img1.src = "clearpixeldot.png";
}
if ((thumb2).getAttribute("src") == "") {
thumb2.style.display = "none";
img2.style.display = "none";
thumb2.src = "clearpixeldot.png";
img2.src = "clearpixeldot.png";
}
if ((thumb3).getAttribute("src") == "") {
thumb3.style.display = "none";
img3.style.display = "none";
thumb3.src = "clearpixeldot.png";
img3.src = "clearpixeldot.png";
}
if ((thumb4).getAttribute("src") == "") {
thumb4.style.display = "none";
img4.style.display = "none";
thumb4.src = "clearpixeldot.png";
img4.src = "clearpixeldot.png";
}
if ((thumb5).getAttribute("src") == "") {
thumb5.style.display = "none";
img5.style.display = "none";
thumb5.src = "clearpixeldot.png";
img5.src = "clearpixeldot.png";
}
if ((thumb6).getAttribute("src") == "") {
thumb6.style.display = "none";
img6.style.display = "none";
thumb6.src = "clearpixeldot.png";
img6.src = "clearpixeldot.png";
}
if ((thumb7).getAttribute("src") == "") {
thumb7.style.display = "none";
img7.style.display = "none";
thumb7.src = "clearpixeldot.png";
img7.src = "clearpixeldot.png";
}
if ((thumb8).getAttribute("src") == "") {
thumb8.style.display = "none";
img8.style.display = "none";
thumb8.src = "clearpixeldot.png";
img8.src = "clearpixeldot.png";
}
if ((thumb9).getAttribute("src") == "") {
thumb9.style.display = "none";
img9.style.display = "none";
thumb9.src = "clearpixeldot.png";
img9.src = "clearpixeldot.png";
}
if ((thumb10).getAttribute("src") == "") {
thumb10.style.display = "none";
img10.style.display = "none";
thumb10.src = "clearpixeldot.png";
img10.src = "clearpixeldot.png";
}
if ((thumb11).getAttribute("src") == "") {
thumb11.style.display = "none";
img11.style.display = "none";
thumb11.src = "clearpixeldot.png";
img11.src = "clearpixeldot.png";
}
if ((thumb12).getAttribute("src") == "") {
thumb12.style.display = "none";
img12.style.display = "none";
thumb12.src = "clearpixeldot.png";
img12.src = "clearpixeldot.png";
}
}
</script>
最佳答案
为了获得所有图像,您将必须使用:
var allImgs = document.querySelectorAll('.thumbs img');
现在,您可以循环执行它们的逻辑,
for ( var counter = 1; counter <= allImgs.length; counter++)
{
var thumb = document.getElementById( "thumb" + counter );
var img = document.getElementById( "img" + counter );
if ( img && thumb && thumb.getAttribute("src") == "") //check if the element exists to avoid any run time issues
{
thumb.style.display = "none";
img.style.display = "none";
thumb.src = "clearpixeldot.png";
img.src = "clearpixeldot.png";
}
}
这将是动态的,适用于您的div中具有类
thumbs
的任何数量的图像。关于javascript - JavaScript如何使用数组和循环而不是多个if语句,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/35402814/