java - 为什么将字符串转换为整数时会出现NumberFormatException？

这是我的代码：

 public void setAreaAccessPoints(){
    String mac = "",essid = "",status = "";
    int strength = 0,kanali = 0;
    List<String> AccessPoints = new ArrayList<String>(); //i lista me ta access points
    String temp;
    try{
        String[] command = {"/bin/sh", "-c", "sudo iwlist " + wirelessName + " scanning | grep -A5 \"Cell\" "};
        Process child = Runtime.getRuntime().exec(command);
        BufferedReader r = new BufferedReader(new InputStreamReader(child.getInputStream()));
        while((temp = r.readLine()) != null){
            if(temp.contains("Cell")){
                String[] info = temp.split(" ");
                mac = info[3];
                System.out.println(mac);
                do{
                    temp = r.readLine();
                    if(temp.contains("ESSID:")){
                        essid = temp.replace("ESSID:","");
                    }
                    if(temp.contains("Frequency:")){
                        String[] info1 = temp.split(" ");
                        info1[3] = info1[3].replace(")","");
                        kanali = Integer.parseInt(info1[3]);
                    }
                    if(temp.contains("Mode:")){
                        status = temp.replace("Mode:","");
                    }
                    if(temp.contains("Quality=")){
                        String[] info2 = temp.split(" ");
                        info2[3] = info2[3].replace("level=","");
                        strength = Integer.parseInt(info2[3]);
                    }
                    if(temp.contains("Protocol:")){
                        temp = r.readLine();
                    }
                }while(!(temp.contains("Cell")));
                AccessPoint newAP = new AccessPoint(mac,essid,kanali,status,strength);
                AccessPoints.add(newAP.toString());  //vazoume ta access points sti lista san strings
            }
        }
        r.close();
        for(String s : AccessPoints)
            System.out.println(s);
    }catch(IOException e){e.printStackTrace();}
}

我正在解析的输出看起来像这样：

      Cell 04 - Address: 00:05:59:30:C1:7C
                Protocol:802.11b/g
                ESSID:"NA home"
                Mode:Managed
                Frequency:2.437 GHz (Channel 6)
                Quality=2/100  Signal level=-89 dBm  Noise level=-92 dBm
  --
      Cell 05 - Address: 00:05:59:43:AE:C9
                Protocol:802.11b/g
                ESSID:"NetFasteR IAD 2 (PSTN)"
                Mode:Managed
                Frequency:2.437 GHz (Channel 6)
                Quality=0/100  Signal level=-91 dBm  Noise level=-94 dBm
  --
      Cell 06 - Address: 00:05:59:3B:C1:FA
                Protocol:802.11b/g
                ESSID:"Kpanagiotou"
                Mode:Managed
                Frequency:2.437 GHz (Channel 6)
                Quality=0/100  Signal level=-91 dBm  Noise level=-94 dBm
  --

错误出现在两行"strength = Integer.parseInt(info2[2]);"和"kanali = Integer.parseInt(info1[3]);" ...我似乎无法弄清楚问题出在哪里。当我分割字符串时，根据输出，我想要的信息在第二和第三字段中。那么，为什么要尝试传递null字符串进行整数解析呢？

堆栈跟踪：

 Exception in thread "Thread-1" java.lang.NumberFormatException: For input string: ""
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:504)
    at java.lang.Integer.parseInt(Integer.java:527)
    at askisi1.Wireless.setAreaAccessPoints(Wireless.java:213)
    at askisi1.Wireless.run(Wireless.java:43)
    at java.lang.Thread.run(Thread.java:722)

最佳答案

线

Quality=2/100  Signal level=-89 dBm  Noise level=-92 dBm

包含双精度空格，因此在split结果中，您有空的String，非空的String不在您认为的索引处。

用索引输出打印出"Quality=2/100 Signal level=-89 dBm Noise level=-92 dBm".split(" ");的结果

0: Quality=2/100
1:
2: Signal
3: level=-89
4: dBm
5:
6: Noise
7: level=-92
8: dBm

您的文件中似乎有前导空格，因此带有非空String的索引将在之后出现。