我正在写一个python tile map editor。我使用的是自行设计的代码来编写和解析某些文件,但是代码非常混乱,因此为了简单起见,我切换到JSON。
我的json文件是这样手工制作的:
{ "Level" :
{
"levelName": "simpleLevel",
"background": [[12, 2,12, 2, 1, 2, 3, 3, 1, 1],
[ 1, 1, 7, 8, 5, 6, 7, 8,12, 3],
[ 1, 3, 1, 3,12,10,10, 1,12,12],
[ 2,12, 0, 4,10, 3,12, 2,12,12],
[12,12, 1, 1,10, 3,12, 2,12, 1],
[12,12,12, 0,10, 2, 1,12, 1,12],
[ 3,12, 3,12, 0, 2, 2,12,12, 3],
[ 1,12, 1,12, 1, 1,12,12, 3,12],
[ 3,12, 0,12,12,12,12,12, 3, 3],
[12, 3, 1, 2, 3,12,12,12, 1,12]],
"foreground": [[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 2, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 3, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
}
}
但是,当我使用
json.dump(self.x, f)
时,我的输出在一行中,而当我尝试使用这些参数sort_keys=True, indent=4, separators=(',', ': ')
时,我得到了一千个换行符。我只想要与手工文件类似的东西,因为它更易于手动阅读和编辑。我可以找到一些简单数组的解决方案,但不适用于2d数组。有简单的答案还是我应该自己编码?
编辑:
为我自己编码(在网络上有一些帮助。)
def fwriteKeyVals(data, f, indent=0):
if isinstance(data, list):
f.write( "\n" + " " * indent + "[" )
for i in range(len(data) ):
if ( i == 0):
f.write( "[" )
else:
f.write( " " * indent + " [" )
for j in range(len(data[0])):
f.write( "%3d" % data[i][j] )
f.write( "," ) if j != len(data[0])-1 else (f.write( "]," ) if i != len(data)-1 else f.write( "]" ))
f.write( "\n" ) if i != len(data)-1 else f.write( "]" )
elif isinstance(data, dict):
f.write( "\n" + " " * indent + "{" )
for k, v in data.iteritems():
f.write( "\n" + " " * indent + "\"" + k + "\"" + ": ")
fwriteKeyVals(v, f, indent + 1)
if( data.keys()[-1] != k):
f.write( "," )
f.write( "\n" + " " * indent + "}" )
else:
f.write("\"" + data + "\"")
用法是:
fwriteKeyVals(x, f)
其中
x = json.load(f)
和f
是我用f = open( map , "wb" )
加载的文件。 最佳答案
您应该签出pprint
,这是用于Python数据结构的Python模块。以下代码应为您提供所需的打印:
# x -> your json dict
import pprint
pp = pprint.PrettyPrinter(indent=4)
pp.pprint(x)