我想我这里少了点小东西。我正在测试python framework flask和flask mongoalchemy,并希望将实体转换为json输出。这是我的代码(摘要):
from flask import Flask
from flaskext.mongoalchemy import MongoAlchemy
try:
from bson.objectid import ObjectId
except:
pass
#a bunch of code to open the mongoDB
class ClassA(db.Document):
title = db.StringField()
field1 = db.StringField()
field2 = db.BoolField()
@app.route('/api/classA', methods=['GET'])
def api_list_all
a = ClassA.query.all()
result = []
for b in a:
result.append(b.wrap())
print result
return json.dumps(result)
如果没有json.dumps行,print语句将提示正确的结果。但只有当我对result运行json.dumps时,它才会产生:
类型错误:objectid(“…”)不是json可序列化的
我错过了什么?
最佳答案
结果是某种类型的mongo文档,其中包含objectid类型的内容,您必须告诉json如何反序列化。对于其他特定于Mongo的类型,例如referenceField()、embeddeddocumentField()等,您也会遇到同样的问题。
您必须编写一个反序列化函数,可以将其传递给json。我用的是:
def encode_model(obj, recursive=False):
if obj is None:
return obj
if isinstance(obj, (mongoengine.Document, mongoengine.EmbeddedDocument)):
out = dict(obj._data)
for k,v in out.items():
if isinstance(v, ObjectId):
if k is None:
out['_id'] = str(v)
del(out[k])
else:
# Unlikely that we'll hit this since ObjectId is always NULL key
out[k] = str(v)
else:
out[k] = encode_model(v)
elif isinstance(obj, mongoengine.queryset.QuerySet):
out = encode_model(list(obj))
elif isinstance(obj, ModuleType):
out = None
elif isinstance(obj, groupby):
out = [ (g,list(l)) for g,l in obj ]
elif isinstance(obj, (list)):
out = [encode_model(item) for item in obj]
elif isinstance(obj, (dict)):
out = dict([(k,encode_model(v)) for (k,v) in obj.items()])
elif isinstance(obj, datetime.datetime):
out = str(obj)
elif isinstance(obj, ObjectId):
out = {'ObjectId':str(obj)}
elif isinstance(obj, (str, unicode)):
out = obj
elif isinstance(obj, float):
out = str(obj)
else:
raise TypeError, "Could not JSON-encode type '%s': %s" % (type(obj), str(obj))
return out
然后将结果处理为:
return json.dumps(result, default=encode_model)
或是有这种效果的东西。