我的Json是:
{
"Response": {
"Asset": [
{
"id": 2461,
"name": "TestAsset7771",
"model_name": "TestModel777",
"serial_number": "TestAsset7771",
"current_data": {
"timestamp": "",
"name": "Temperature",
"value": "?"
}
},
{
"id": 2448,
"model_id": 1229,
"name": "TestAsset777",
"model_name": "TestModel777",
"serial_number": "TestAsset777",
"current_data": {
"timestamp": "",
"name": "Temperature",
"value": "?"
}
}
]
}
}
我的代码是:
JSONObject outerObject = new JSONObject(jsonObj.toString());
JSONObject innerObject = outerObject.getJSONObject("Response");
JSONArray jsonArray = innerObject.getJSONArray("Asset");
for (int i = 0, size = jsonArray.length(); i < size; i++)
{
JSONObject objectInArray = jsonArray.getJSONObject(i);
String[] elementNames = JSONObject.getNames(objectInArray)
for (String elementName : elementNames)
{
String value = objectInArray.getString(elementName);
System.out.printf("name=%s, value=%s\n", elementName, value);
}
}
对于内部数组-即当前数据,正在获取的值为:
名称= current_data,
value = {“ timestamp”:“”,“ name”:“ Temperature”,“ value”:“?”}
我如何放置另一个内部数组,以便我可以获得
“ timestamp”:“”,“ name”:“温度”,“ value”:“?”在单独的变量中,而不是完整的JSON
最佳答案
最好使用Gson解析JSON。无论如何,如果您决定照此进行,请尝试:
您有一个像这样的课程:
class CurrentData{
String name,timestamp,value;
void print(){
System.out.printf("name=%s, timestamp=%s, value=%s\n", name,timestamp, value);
}
}
现在,如下更改您的for循环:
for (String elementName : elementNames)
{
if(!elementName.equals("current_data")){
String value = objectInArray.getString(elementName);
System.out.printf("name=%s, value=%s\n", elementName, value);
}
else{
CurrentData obj=new CurrentData();// You can use array of objects declaring outside the loop as your need
JSONObject curr_object=objectInArray.getJSONObject("current_data");
obj.name=curr_object.getString("name");
obj.timestamp=curr_object.getString("timestamp");
obj.value=curr_object.getString("value");
obj.print();
}
}