我想在Android上使用Mockito。我想用它来回拨电话。
这是我的测试:
public class LoginPresenterTest {
private User mUser = new User();
@Mock
private UsersRepository mUsersRepository;
@Mock
private LoginContract.View mLoginView;
/**
* {@link ArgumentCaptor} is a powerful Mockito API to capture argument values and use them to
* perform further actions or assertions on them.
*/
@Captor
private ArgumentCaptor<LoginUserCallback> mLoadLoginUserCallbackCaptor;
private LoginPresenter mLoginPresenter;
@Before
public void setupNotesPresenter() {
// Mockito has a very convenient way to inject mocks by using the @Mock annotation. To
// inject the mocks in the test the initMocks method needs to be called.
MockitoAnnotations.initMocks(this);
// Get a reference to the class under test
mLoginPresenter = new LoginPresenter(mUsersRepository, mLoginView);
// fixtures
mUser.setFirstName("Von");
mUser.setLastName("Miller");
mUser.setUsername("von.miller@broncos.us");
mUser.setPassword("Broncos50superBowlWinners");
}
@Test
public void onLoginFail_ShowFail() {
// When try to login
mLoginPresenter.login("von.miller@broncos.us", "notGoodPassword");
// Callback is captured and invoked with stubbed user
verify(mUsersRepository).login(eq(new User()), mLoadLoginUserCallbackCaptor.capture());
mLoadLoginUserCallbackCaptor.getValue().onLoginComplete(eq(mUser));
// The login progress is show
verify(mLoginView).showLoginFailed(anyString());
}
但我犯了个错误:
Argument(s) are different! Wanted:
mUsersRepository.login(
ch.example.project.Model.User@a45f686,
<Capturing argument>
);
-> at example.ch.project.Login.LoginPresenterTest.onLoginFail_ShowFail(LoginPresenterTest.java:94)
Actual invocation has different arguments:
mUsersRepository.login(
ch.example.project.Model.User@773bdcae,
ch.example.project.Login.LoginPresenter$1@1844b009
);
也许问题是第二个实际参数是ch.example.project.login.loginpresenter$1@1844b009?
我跟着:https://codelabs.developers.google.com/codelabs/android-testing/#5
感谢您的帮助=)
编辑
我尝试测试的方法(loginpresenter):
@Override
public void login(String email, String password) {
mLoginView.showLoginInProgress();
User user = new User();
user.setUsername(email);
user.setPassword(password);
mUsersRepository.login(user, new UsersRepository.LoginUserCallback() {
@Override
public void onLoginComplete(User loggedUser) {
mLoginView.showLoginComplete();
}
@Override
public void onErrorAtAttempt(String message) {
mLoginView.showLoginFailed(message);
}
});
}
最佳答案
eq(new User())
当使用
eq
时(或者根本不使用匹配器),mockito使用传入实例的equals
方法比较参数。除非为用户对象定义了灵活的equals
实现,否则很可能会失败。考虑使用
isA(User.class)
,这将简单地验证对象instanceof User
,或any()
或anyObject()
是否跳过完全匹配第一个参数。