android - Mockito和回调返回“参数不同!”

我想在Android上使用Mockito。我想用它来回拨电话。
这是我的测试：

public class LoginPresenterTest {


private User mUser = new User();

@Mock
private UsersRepository mUsersRepository;

@Mock
private LoginContract.View mLoginView;

/**
 * {@link ArgumentCaptor} is a powerful Mockito API to capture argument values and use them to
 * perform further actions or assertions on them.
 */
@Captor
private ArgumentCaptor<LoginUserCallback> mLoadLoginUserCallbackCaptor;

private LoginPresenter mLoginPresenter;

@Before
public void setupNotesPresenter() {
    // Mockito has a very convenient way to inject mocks by using the @Mock annotation. To
    // inject the mocks in the test the initMocks method needs to be called.
    MockitoAnnotations.initMocks(this);

    // Get a reference to the class under test
    mLoginPresenter = new LoginPresenter(mUsersRepository, mLoginView);

    // fixtures
    mUser.setFirstName("Von");
    mUser.setLastName("Miller");
    mUser.setUsername("[e-mail]");
    mUser.setPassword("Broncos50superBowlWinners");
}

@Test
public void onLoginFail_ShowFail() {

    // When try to login
    mLoginPresenter.login("[e-mail]", "notGoodPassword");


    // Callback is captured and invoked with stubbed user
    verify(mUsersRepository).login(eq(new User()), mLoadLoginUserCallbackCaptor.capture());
    mLoadLoginUserCallbackCaptor.getValue().onLoginComplete(eq(mUser));

    // The login progress is show
    verify(mLoginView).showLoginFailed(anyString());
}

但我犯了个错误：

Argument(s) are different! Wanted:
mUsersRepository.login(
    ch.example.project.Model.User@a45f686,
    <Capturing argument>
);
-> at example.ch.project.Login.LoginPresenterTest.onLoginFail_ShowFail(LoginPresenterTest.java:94)
Actual invocation has different arguments:
mUsersRepository.login(
    ch.example.project.Model.User@773bdcae,
    ch.example.project.Login.LoginPresenter$1@1844b009
);

也许问题是第二个实际参数是ch.example.project.login.loginpresenter$1@1844b009？
我跟着：https://codelabs.developers.google.com/codelabs/android-testing/#5
感谢您的帮助=）
编辑
我尝试测试的方法（loginpresenter）：

@Override
public void login(String email, String password) {

    mLoginView.showLoginInProgress();

    User user = new User();
    user.setUsername(email);
    user.setPassword(password);

    mUsersRepository.login(user, new UsersRepository.LoginUserCallback() {

        @Override
        public void onLoginComplete(User loggedUser) {
            mLoginView.showLoginComplete();
        }

        @Override
        public void onErrorAtAttempt(String message) {
            mLoginView.showLoginFailed(message);
        }
    });

}

最佳答案

eq(new User())

当使用eq时（或者根本不使用匹配器），mockito使用传入实例的equals方法比较参数。除非为用户对象定义了灵活的equals实现，否则很可能会失败。
考虑使用isA(User.class)，这将简单地验证对象instanceof User，或any()或anyObject()是否跳过完全匹配第一个参数。