嗨,我正在尝试使用jackson-dataformat-xml 2.7.3 XmlMapper将我的POJO转换为xml。我在POJO类中使用杰克逊注释,如以下代码所示,但是我在列表的每个标记中附加了一些唯一的ID。我如何删除这些唯一的ID。

//下面是ElementTag类

import java.util.List;

import
com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;
/**
*Element class
*/
public class ElementTag {
@JacksonXmlProperty(localName = "FL")
@JacksonXmlElementWrapper(useWrapping = false)
private List<ProfessionalLeadDetails> pf;

/**
 * @return the pf
 */
public List<ProfessionalLeadDetails> getPf() {
    return pf;
}

/**
 * @param pf the pf to set
 */
public void setPf(List<ProfessionalLeadDetails> pf) {
    this.pf = pf;
}
}


//以下是ProfessionalLeadDetails类

import java.io.Serializable;

import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlProperty;


public class ProfessionalLeadDetails implements Serializable {

/** The Constant serialVersionUID. */
private static final long serialVersionUID = 1L;


@JacksonXmlProperty(isAttribute = true)
 private String val;

 private String value;
    /**
 * @return the val
 */
public String getVal() {
    return val;
}
/**
 * @param val the val to set
 */
public void setVal(String val) {
    this.val = val;
}
/**
 * @return the value
 */
public String getValue() {
    return value;
}
/**
 * @param value the value to set
 */
public void setValue(String value) {
    this.value = value;
}
}


//在主要方法中使用XmlMapper转换为xml

XmlMapper xmlMapper = new XmlMapper();
    ElementTag et = new ElementTag();
    List<ProfessionalLeadDetails> pfList = new
ArrayList<ProfessionalLeadDetails>();
    ProfessionalLeadDetails pf = new ProfessionalLeadDetails();
    pf.setVal("First Name");
    pf.setValue("Sandeep");
    pfList.add(pf);
    pf = new ProfessionalLeadDetails();
    pf.setVal("Email");
    pf.setValue("Sandeep@gmail.com");
    pfList.add(pf);

    pfList.add(pf2);
    et.setPf(pfList);
    try {

System.out.println(xmlMapper.writer()
.with(SerializationFeature.WRAP_ROOT_VALUE)
            .withRootName("Leads").writeValueAsString(et));
} catch (JsonProcessingException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}


但是我在val之前附加了一些独特的ID,例如zdef1999262822:如下所示:
输出值

  <Leads xmlns=""><FL zdef2041716767:val="First Name"><value>Sandeep</value></FL><FL zdef1999262822:val="Email"><value>Sandeep@gmail.com</value></FL></Leads>


期望的输出:

 <Leads xmlns=""><FL val="First Name"><value>Sandeep</value></FL><FL val="Email"><value>Sandeep@gmail.com</value></FL></Leads>


提前致谢!

最佳答案

确保使用Woodstox Stax实现,而不是Stax实现Oracle与JDK捆绑在一起。这通常是通过添加Maven依赖项来明确包含woodstox jar来完成的。在XML模块上对此进行了解释

<dependency>
          <groupId>org.codehaus.woodstox</groupId>
          <artifactId>woodstox-core-asl</artifactId>
          <version>4.4.1</version>
        </dependency>

关于java - @JacksonXmlProperty(isAttribute = true)使用Jackson XmlMapper附加唯一ID,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45987023/

10-11 22:14
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