在stackoverflow上有很多有关如何使用Gson反序列化json数组的信息。

但是,如何在jettison中使用XStream来做同样的事情?

这是json:

{"entity":[{"id":"1", "name":"aaa"}, {"id":"2", "name":"bbb"}]}

这是我尝试解析它的XStream代码:
XStream xstream = new XStream(new JettisonMappedXmlDriver());
xstream.alias("entity", Entity[].class);
return (Entity[])xstream.fromXML(jsonString);

我有以下异常(exception):
com.thoughtworks.xstream.converters.ConversionException: id : id

最佳答案

使用数组,我无法运行它,但是有一个列表:

Java的:

package de.mosst.spielwiese;

import java.io.InputStream;
import java.util.ArrayList;
import java.util.List;

import org.junit.Test;

import com.thoughtworks.xstream.XStream;
import com.thoughtworks.xstream.annotations.XStreamAlias;
import com.thoughtworks.xstream.io.json.JettisonMappedXmlDriver;

import lombok.Data;

public class XStreamDeserializeJsonWithJettison {

    @Test
    @SuppressWarnings("unchecked")
    public void smokeTest() {
        InputStream file = XStreamDeserializeJsonWithJettison.class.getResourceAsStream("XStreamDeserializeJsonWithJettison.json");
        XStream xStream = new XStream(new JettisonMappedXmlDriver());
        xStream.processAnnotations(Entity.class);

        List<Entity> entities = (List<Entity>) xStream.fromXML(file);
        System.out.println(entities);
    }

    @Data
    @lombok.AllArgsConstructor
    @XStreamAlias("entity")
    class Entity {
        String id;
        String name;
    }
}

XML:
{
    "list": [
        {
            "entity": [
                {
                    "id": 1,
                    "name": "odin"
                },
                {
                    "id": 2,
                    "name": "dwa"
                }
            ]
        }
    ]
}

10-07 19:08
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